2016-03-11 61 views
0

所以我現在有一種醜陋的情況。我有一個包含「getAllData」方法的類版本。該方法返回InputStream的Supplier。在Java中使用供應商流<InputStream>給予澤西島響應

public class Revision { 
    private String id; 
    private Supplier<InputStream> allData; 

    public Revision(String id, Supplier<InputStream> allData) { 
     this.id = id; 
     this.allData = allData; 
    } 

    public getAllData() { 
     return allData; 
    } 
} 

比方說,我有2個修訂。他們宣稱,像這樣:

Supplier<InputStream> revisionValue1 =() -> new ByteArrayInputStream(
      "{\"name\":\"George\", \"state\":\"Colorado\", \"Exp\":\"lots\"}".getBytes()); 
Revision revision1 = new Revision("Id1", revisionValue1); 

Supplier<InputStream> revisionValue2 =() -> new ByteArrayInputStream(
      "{\"name\":\"Sean\", \"state\":\"New York\"}".getBytes()); 
Revision revision2 = new Revision("Id2", revisionValue2); 

而且他們放入地圖成員:

Map<String, Revision> revisions = new HashMap<>(); 
revisions.put("Id1", revision1); 
revisions.put("Id2", revision2); 

電流的方法(這本身可能不是寫得很好)返回流:

public Stream<Revision> getRevisions() { 
    return revisions.values().stream(); 
} 

現在在我的Jersey代碼中,我需要弄清楚如何將這些值作爲Json格式的響應返回。所以結果應該是這樣的:

[ 
{ 
    "name": "George", 
    "state": "Colorado", 
    "Exp": "lots" 
}, 
{ 
    "name": "Sean", 
    "state": "New York" 
} 
] 

我試圖做到這一點,即使作爲純文本,這是行不通的。我想要的是:

@Produces(MediaType.TEXT_PLAIN) 
public Response getRevisions(...) { 

    Stream<Revision> revisionObjects = getRevisions(); 

    // each Revision option has a getAllData() method that needs called, which returns Supplier<InputStream> 
    // each Supplier<InputStream> contains, essentially, a Json record 

    // attempt at creating a StreamingOutput that can be sent as a response 
    if (revisionObjects != null) { 
     StreamingOutput stream = os -> { 
      Writer writer = new OutputStreamWriter(os); 
      Iterator<Revision> revisionIterator = revisionObjects.iterator(); 
      while (revisionIterator.hasNext()) { 
       Revision next = revisionIterator.next(); 
       writer.write(next.getAllData().get().toString()); 
      } 
      writer.flush(); 
     }; 
     return Response.ok(stream).build(); 
    } 
    return Response.noContent().build(); 
} 

這是返回結果一樣:

[email protected]@ba0b09 

這我假設是因爲有需要是「的toString()」方法之前一個額外的步驟作家。

對不起,這是多久,我只是想提供的細節。有誰知道如何讓這個工作?理想情況下,我希望它能用JSON做出迴應,但即使是純文本也是一個巨大的進步。

P.S.我仍然試圖圍繞InputStreams和OutputStreams進行封裝,所以很有可能,我有一些不合邏輯的東西。

回答

1
@Produces(MediaType.TEXT_PLAIN) 
public Response getRevisions(...) { 

    Stream<Revision> revisionObjects = getRevisions(); 

    // each Revision option has a getAllData() method that needs called, which returns Supplier<InputStream> 
    // each Supplier<InputStream> contains, essentially, a Json record 

    // attempt at creating a StreamingOutput that can be sent as a response 
    if (revisionObjects != null) { 
      Iterator<Revision> revisionIterator = revisionObjects.iterator(); 
      List<JSONObject> revisionsResponse = new ArrayList<JSONObject>(); 
      while (revisionIterator.hasNext()) { 
       BufferedReader streamReader = new BufferedReader(new InputStreamReader(revisionIterator.next().getAllData().get(), "UTF-8")); 
       StringBuilder responseStrBuilder = new StringBuilder(); 

       String inputStr; 
       while ((inputStr = streamReader.readLine()) != null) 
         responseStrBuilder.append(inputStr); 
       revisionsResponse.add(new JSONObject(responseStrBuilder.toString()); 
      } 

      return Response.ok(revisionsResponse).build(); 
    } 
    return Response.noContent().build(); 
} 
+0

「getAllData()」位於修訂對象中,該對象是流中的單個元素。我將如何將getAllData()替換爲查看調用它的單個修訂版的東西? – user2869231

+0

我編輯了這篇文章。這是你要求的嗎? – Sanj

+0

revisionResponse包含我想要的值,這非常棒。不過,我現在正在收到一個服務器錯誤,我認爲它對於返回一個ArrayList作爲響應感到憤怒。在迴應中列出之前是否需要完成清單? – user2869231