如何將python方法/插槽連接到QML信號?它看起來像QtObject.connect()用於在PyQt4中工作,但它是no longer available in PyQt5。PyQt5 QML信號到Python插槽?
#Sample QML File (stack.qml)
import QtQuick 2.0
Rectangle {
MouseArea {
anchors.fill: parent
onClicked: {
// relay this to python
}
}
}
-
#Sample Python File
from PyQt5.QtCore import QUrl
from PyQt5.QtGui import QGuiApplication
from PyQt5.QtQuick import QQuickView
if __name__ == '__main__':
import os
import sys
app = QGuiApplication(sys.argv)
view = QQuickView()
view.setWidth(500)
view.setHeight(500)
view.setTitle('Hello PyQt')
view.setResizeMode(QQuickView.SizeRootObjectToView)
view.setSource(QUrl.fromLocalFile(os.path.join(os.path.dirname(__file__),'stack.qml')))
def on_qml_mouse_clicked(mouse_event):
print 'mouse clicked'
view.show()
qml_rectangle = view.rootObject()
# this technique doesn't work #############################
qml_rectangle.mousePressEvent.connect(on_qml_mouse_clicked)
sys.exit(app.exec_())
一些PyQt的例子傳遞一個對象到經由「setContextProperty」的QML上下文,然後中繼QML事件槽在該對象上但方法似乎迂迴。有沒有更好的辦法?
的偉大工程,找到更多的信息!謝謝! – berg