0
前言:我還是一個Haskell noob,所以如果我遺漏了一些明顯的東西,請原諒我。我正在嘗試爲具有非標準數據類型(電子郵件地址)字段的記錄數據類型編寫aeson ToJSON和FromJSON實例。在Aeson記錄中使用自定義數據類型
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE DeriveGeneriC#-}
{-# LANGUAGE LambdaCase #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE RecordWildCards #-}
{-# LANGUAGE TypeOperators #-}
module User where
import Control.Monad.Trans.Except
import Data.Aeson
import Data.ByteString.Char8 (pack)
import Data.Maybe
import GHC.Generics
import Servant
import Text.Email.Validate
type UserApi =
"user" :> Get '[JSON] [User] :<|>
"user" :> Capture "userId" Integer :> Get '[JSON] User
userServer :: Server UserApi
userServer =
getUsers :<|>
getUserById
getUsers :: Handler [User]
getUsers = return [exampleUser]
getUserById :: Integer -> Handler User
getUserById = \ case
0 -> return exampleUser
_ -> throwE err404
exampleUser :: User
exampleUser = User 0 "L. Smith" (fromJust (emailAddress "[email protected]")) Base
-- * user info
data UserLevel = Base | Admin
deriving (Eq, Show, Generic)
data User
= User {
userId :: Integer,
userName :: String,
userEmail :: EmailAddress,
userLevel :: UserLevel
}
deriving (Eq, Show, Generic)
instance ToJSON User where
toJSON (User userId userName userEmail userLevel) =
object ["userId" .= userId, "userName" .= userName, "userEmail" .= show userEmail, "userLevel" .= show userLevel]
instance FromJSON User where
parseJSON = withObject "user" $ \o -> do
userId <- o .: "userId"
userName <- o .: "userName"
userEmail <- do s <- emailAddress (pack (o .: "age"))
case s of
Nothing -> fail "Invalid email address"
Just x -> return x
userLevel <- o .: "userLevel"
return User{..}
GHC輸出這些錯誤:
/home/gigavinyl/Projects/ordermage/src/components/User.hs:59:26: error:
• Couldn't match type ‘Maybe’
with ‘aeson-0.11.2.1:Data.Aeson.Types.Internal.Parser’
Expected type: aeson-0.11.2.1:Data.Aeson.Types.Internal.Parser
EmailAddress
Actual type: Maybe EmailAddress
• In a stmt of a 'do' block: s <- emailAddress (pack (o .: "age"))
In a stmt of a 'do' block:
userEmail <- do { s <- emailAddress (pack (o .: "age"));
case s of {
Nothing -> fail "Invalid email address"
Just x -> return x } }
In the expression:
do { userId <- o .: "userId";
userName <- o .: "userName";
userEmail <- do { s <- emailAddress (pack (o .: "age"));
case s of {
Nothing -> ...
Just x -> ... } };
userLevel <- o .: "userLevel";
.... }
/home/gigavinyl/Projects/ordermage/src/components/User.hs:59:46: error:
• Couldn't match type ‘aeson-0.11.2.1:Data.Aeson.Types.Internal.Parser
a0’
with ‘[Char]’
Expected type: String
Actual type: aeson-0.11.2.1:Data.Aeson.Types.Internal.Parser a0
• In the first argument of ‘pack’, namely ‘(o .: "age")’
In the first argument of ‘emailAddress’, namely
‘(pack (o .: "age"))’
In a stmt of a 'do' block: s <- emailAddress (pack (o .: "age"))
/home/gigavinyl/Projects/ordermage/src/components/User.hs:61:23: error:
• Couldn't match expected type ‘EmailAddress’
with actual type ‘Maybe t0’
• In the pattern: Nothing
In a case alternative: Nothing -> fail "Invalid email address"
In a stmt of a 'do' block:
case s of {
Nothing -> fail "Invalid email address"
Just x -> return x }
/home/gigavinyl/Projects/ordermage/src/components/User.hs:62:23: error:
• Couldn't match expected type ‘EmailAddress’
with actual type ‘Maybe EmailAddress’
• In the pattern: Just x
In a case alternative: Just x -> return x
In a stmt of a 'do' block:
case s of {
Nothing -> fail "Invalid email address"
Just x -> return x }
如何正確寫這些情況?