Replay Tic Tac Toe

Question

我正在寫井字遊戲，需要詢問用戶是否想再次玩（y/n）。我有遊戲的工作，我只是不知道如果用戶點擊y如何循環它，和/或如果用戶點擊n終止它。我已經嘗試了幾種不同的東西，但似乎無法找出它們中的任何一個，所以這只是我發佈的工作代碼。任何幫助將不勝感激！直到他們與回答

import java.util.Scanner; 
public class Assignment7 { 

    public static int row, col; 
    public static Scanner scan = new Scanner(System.in); 
    public static char[][] board = new char[3][3]; 
    public static char turn = 'X'; 
    static Scanner input = new Scanner(System.in); 

    public static void main(String[] args) { 
     /*create for-loop 
    * 9 empty spots, 3x3 
     */ 

     for (int i = 0; i < 3; i++) { 
      for (int j = 0; j < 3; j++) { 
       board[i][j] = '_'; 
      } 
     } 
     Play(); 
    } 

    public static void Play() { 
     //find if game over 
     boolean playing = true; 
     PrintBoard(); 

     while (playing) { 
      System.out.println("Please enter a row, then a column: "); 
      //make row next thing player types 
      row = scan.nextInt() - 1; 
      //same with column 
      col = scan.nextInt() - 1; 
      board[row][col] = turn; 
      if (GameOver(row, col)) { 
       playing = false; 
       System.out.println("Game over! Player " + turn + " wins!"); 

      } 
      PrintBoard(); 
      //switch players after entries 
      if (turn == 'X') { 
       turn = 'O'; 
      } else { 
       turn = 'X'; 
      } 
     } 

    } 

    public static void PrintBoard() { 

     for (int i = 0; i < 3; i++) { 
      System.out.println(); 
      for (int j = 0; j < 3; j++) { 
       //get dividers on left 
       if (j == 0) { 
        System.out.print("| "); 
       } 
       // get dividers in all 
       System.out.print(board[i][j] + " | "); 
      } 
     } 
     //enter space after board 
     System.out.println(); 
    } 

    public static boolean GameOver(int rMove, int cMove) { 
     // Check perpendicular victory 
     if (board[0][cMove] == board[1][cMove] 
       && board[0][cMove] == board[2][cMove]) { 
      return true; 
     } 
     if (board[rMove][0] == board[rMove][1] 
       && board[rMove][0] == board[rMove][2]) { 
      return true; 
     } 
     // Check diagonal victory 
     if (board[0][0] == board[1][1] && board[0][0] == board[2][2] 
       && board[1][1] != '_') { 
      return true; 
     } 
     return false; 

    } 
} 

Answer 1

只需使用一個do-while循環，環繞你的「遊戲」代碼...

當Play方法返回時，提示用戶，如果他們想要玩另一個遊戲，循環例如其他任何「Y」，例如

String input = null; 
do { 
    for (int i = 0; i < 3; i++) { 
     for (int j = 0; j < 3; j++) { 
      board[i][j] = '_'; 
     } 
    } 
    Play(); 
    if (scan.hasNextLine()) { 
     scan.nextLine(); 
    } 
    System.out.print("Do you want to play a game [Y/N]? "); 
    input = scan.nextLine(); 
} while ("y".equalsIgnoreCase(input));