我認爲這反映了你的桌子,雖然我使用的名稱,而不是ID的最後兩列:
CREATE TABLE [dbo].[Transaction](
[TransId] [int] NOT NULL,
[DocId] [int] NOT NULL,
[EmpId] [nvarchar](10) NOT NULL,
[FromToId] [nchar](10) NOT NULL
) ON [PRIMARY]
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(1,1,'Jo','From')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(2,1,'Fo','To')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(3,1,'Do','CC')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(4,2,'Jo','From')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(5,2,'Bo','To')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(6,2,'Zo','CC')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(7,3,'Bo','From')
INSERT INTO [Transaction] ([TransId],[DocId],[EmpId],[FromToId])VALUES(8,3,'Go','To')
那麼這個查詢會給你你所要求的結果:
SELECT DISTINCT
t.DocId
,x.[From]
,y.[To]
,z.Cc
FROM [Transaction] t
LEFT JOIN
(
SELECT DocId
,CASE WHEN FromToId = 'From' THEN EmpId END AS [From]
FROM [Transaction]
WHERE CASE WHEN FromToId = 'From' THEN EmpId END IS NOT NULL
) x ON t.DocId = x.DocId
LEFT JOIN
(
SELECT DocId
,CASE WHEN FromToId = 'To' THEN EmpId END AS [To]
FROM [Transaction]
WHERE CASE WHEN FromToId = 'To' THEN EmpId END IS NOT NULL
) y ON t.DocId = y.DocId
LEFT JOIN
(
SELECT DocId
,CASE WHEN FromToId = 'CC' THEN EmpId END AS [Cc]
FROM [Transaction]
WHERE CASE WHEN FromToId = 'Cc' THEN EmpId END IS NOT NULL
) z ON t.DocId = z.DocId
DocId From To Cc
1 Jo Fo Do
2 Jo Bo Zo
3 Bo Go NULL
請格式化您的數據...它不會對齊。 – JonH