在SQLiteDatabase

Question

我試圖用sqlitedatabase，所以在我更新類我得到一個錯誤，這是這裏的PIC http://prntscr.com/djbe3i

這裏來更新我的列表視圖的信息更新的信息是該dbhelper方法的代碼：

public int updateInformation(String old_name, String new_name,String old_hours, String new_hours, String old_department,String new_department,SQLiteDatabase sqLiteDatabase) { 

    ContentValues contentValues = new ContentValues(); 
    contentValues.put(UserContract.NewUserInfo.Name,new_name); 
    contentValues.put(UserContract.NewUserInfo.RenderedHours,new_hours); 
    contentValues.put(UserContract.NewUserInfo.Department,new_department); 

    String selection = UserContract.NewUserInfo.Name + " LIKE ?"; 
    String[] selection_args = {old_name}; 
    int count = sqLiteDatabase.update(UserContract.NewUserInfo.TABLE_NAME,contentValues,selection,selection_args); 
    return count; 

} 

更新類代碼：

public void updateContact(View view) { 

    userDBHelper = new UserDBHelper(getApplicationContext()); 
    sqLiteDatabase = userDBHelper.getWritableDatabase(); 
    String name,hours,department; 

    name = new_name.getText().toString(); 
    hours = new_hours.getText().toString(); 
    department = new_department.getText().toString(); 
int count = userDBHelper.updateInformation(search_id,NewName,NewHours,NewDepartment,sqLiteDatabase); 

} 
} 

編輯：我改變了代碼爲：

public void updateContact(View view) { 

    userDBHelper = new UserDBHelper(getApplicationContext()); 
    sqLiteDatabase = userDBHelper.getWritableDatabase(); 
    String name,hours,department; 

    name = new_name.getText().toString(); 
    hours = new_hours.getText().toString(); 
    department = new_department.getText().toString(); 
    int count = userDBHelper.updateInformation(search,name,hours,department,sqLiteDatabase); 

} 

我仍然收到錯誤，我不明白。

2ND編輯：我明白了，現在好了，我只輸入了錯誤的字符串，我需要的更新接觸我取代了代碼到參數：

int count = userDBHelper.updateInformation(search_id,name,hours,department,sqLiteDatabase); 

DBHelper.updateInformation代碼：

public int updateInformation(String old_name, String new_name, String new_hours,String new_department,SQLiteDatabase sqLiteDatabase) 

Answer 1

我得到了，現在我的參數不匹配，我改變了代碼轉換成固定它：

public int updateInformation(String old_name, String new_name, String new_hours,String new_department,SQLiteDatabase sqLiteDatabase) 

然後改變更新類中的代碼：

int count = userDBHelper.updateInformation(search_id,name,hours,department,sqLiteDatabase);