有這個編碼的問題,如何檢查並顯示贏家?我試圖添加它,但由於函數checkWinner()變成錯誤。井字c + +查看和打印得主
#include <iostream>
using namespace std;
void showBoard(void);
void playerInput(int p);
void checkWinner();
void nextPlayer(int);
int board[3][3]={{0,0,0},{0,0,0},{0,0,0}};
int main()
{
int r;
int c;
int player;
int winner;
int turns;
cout << "******* Tic Tac Toe Game *******" << endl;
showBoard();
nextPlayer(1);
checkWinner();
return 0;
}
輸出板功能:
void showBoard(void)
{
int r;
int c;
for(r=0; r<=2; r++)
{
for(c=0; c<=2; c++)
{
if(board [r][c]==0)
cout << "0 ";
else if (board [r][c]==1)
cout << "1 ";
else
cout << "2 ";
}
cout << endl;
}
}
這是玩家輸入功能:
void playerInput(int p)
{
int row;
int col;
if(p==1)
cout <<"You are player number 1 \n\n";
else
cout <<"You are player number 2 \n\n";
cout<<"Please enter your coordinate:";
cin>>row;
cout<<"\n";
cin>>col;
if(p==1)
board[--row][--col]=1;
if(p==2)
board[--row][--col]=2;
}
繼承人,我現在面對的問題,如何使它顯示的贏家?
void checkWinner()
{
int winner;
for (int i=0; i<=2; i++)
{
if(board[i][0]==board[i][1] && board[i][1]==board[i][2] && board[i][0]!=0)
{
winner=board[i][0];
}
}
for(int i=0; i<=2; i++)
{
if (board[0][i]==board[1][i] && board[1][i]==board[2][i] && board[0][i]!=0)
{
winner=board[0][i];
}
}
if(board[0][0]=board[1][1] && board[1][1]==board[2][2] && board[0][0]!=0)
{
winner=board[0][0];
}
if(board[0][2]=board[1][1] && board[1][1]==board[2][0] && board [0][2]!=0)
{
winner=board[0][2];
}
if(board[0][0]==board[0][1] && board[0][1]==board[0][2]&& board[0][2]==board[0][1]&& board[1][0]==board [1][1]&& board[1][1]==board [1][2]&& board[1][2]==board[2][0]&&board[2][0]==board [2][1]&& board[2][1]==board [2][2] && board [0][0]!=0)
{
winner=0;
}
}
void nextPlayer(int player)
{
playerInput(player);
showBoard();
if(player==1)
player=2;
else
player=1;
nextPlayer(player);
}
問題是遊戲沒有結束,但它仍然要求玩家恢復並不斷更新價值。 點擊下方查看我正面臨的問題。謝謝!
Click to view my output, it doesn't end the game
你說的是什麼**錯誤**? –
'由於函數checkWinner()會變成錯誤'聽起來像這是在你的問題中解釋的重要一點... – John3136
正確地格式化你的代碼顯示了兩個非常明顯的地方,你使用'='但你應該使用' =='。 –