因此,我正在使用AFNetworking 2.0(帶橋接頭的ObjC框架)在本地服務器上發出一些請求。我遵循幾個教程來使用Swift進行編碼。這是代碼:iOS Swift:使用AFNetworking分析響應json
var success = { (operation:AFHTTPRequestOperation!, response:AnyObject!) -> Void in
println(response.description)
successBlock(result:response.description)
}
var failure = { (operation:AFHTTPRequestOperation!, response:NSError!) -> Void in
println(response.description)
errorBlock(error:response.description)
}
var manager = AFHTTPRequestOperationManager()
manager.responseSerializer = AFJSONResponseSerializer();
manager.GET("http://127.0.0.1:8080/api/manufacturer", parameters: nil, success: success, failure: failure)
它檢索json併成功打印它。響應是這樣的:
(
{
"_id" = 539f0973e3c7f4ab1f6078f5;
name = Manufacturer01;
},
{
"_id" = 539f18c5e3c7f4ab1f6078f6;
name = Manufacturer02;
}
)
但是,我無法分析它...我想response[0]
拿到的第一個元素,但是當我嘗試做它崩潰的模擬器,甚至Xcode6:(lldb) > po response[0]
。我嘗試了一切,我看到的每個示例都解釋瞭如何打印結果,但沒有解釋每個字段。
的response
對象看起來是這樣的,當我嘗試調試它:
value = Some {
Some = (instance_type = Builtin.RawPointer = 0x0b240710 -> 0x00bc5da0 (void *)0x00bc5db4: __NSCFArray)
}
任何線索?提前致謝!
我也有這個問題。我如何將JSON Dictionary值賦給字符串變量?我有一個var'var serverID:String?',並嘗試'self.serverID = responseObject [「server_id」]爲?字符串'它崩潰Xcode – Sean
我已經成功的這種方法:http://stackoverflow.com/questions/24259756/unable-to-parse-json-from-afnetworkings-responseobject – heycarsten
@heycarsten不幸的是我得到EXC_BAD_INSTRUCTION在模擬器和EXC_BREAKPOINT上帶有該代碼的設備。 :( – Koesh