數組操作的想法

Question

我有兩個數組。

$Array1 = array("Maza", "Nissan","Tacoma","Cobalt","Explorer"); 

和第二陣列是

array(
    (int) 0 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars' 
    ), 
    (int) 1 => array(
     (int) 0 => 'In stock', 
     (int) 1 => 'Cars/Toyota/Tacoma' 
    ), 
    (int) 2 => array(
     (int) 0 => 'Out of Stock', 
     (int) 1 => 'Cars/Toyota/Celica' 
    ), 
    (int) 3 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars/Ford/Fusion' 
    ), 
    (int) 4 => array(
     (int) 0 => 'Out of Stock', 
     (int) 1 => 'Cars/Ford/Explorer' 
    ), 
    (int) 5 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars/Chevy/Cobalt' 
    ), 
    (int) 6 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars/Nissan' 
    ) 

) 

現在我想看到基於第一和第二陣列上什麼車庫存與否。所以對於Cobalt來說，它會讓我回到In Stock，就像Explorer一樣，它會讓我斷貨。對於馬自達來說，它可以重新調整「不要攜帶」。在那裏，我很困惑的是不管用斜線「/」來爆炸數組[1]，然後查看它。有沒有更簡單/更快的方法來做到這一點。感謝

Answer 1

試試這個：

$cars = array("Maza", "Nissan","Tacoma","Cobalt","Explorer"); 
$stocks=array(
    (int) 0 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars' 
    ), 
    (int) 1 => array(
     (int) 0 => 'In stock', 
     (int) 1 => 'Cars/Toyota/Tacoma' 
    ), 
    (int) 2 => array(
     (int) 0 => 'Out of Stock', 
     (int) 1 => 'Cars/Toyota/Celica' 
    ), 
    (int) 3 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars/Ford/Fusion' 
    ), 
    (int) 4 => array(
     (int) 0 => 'Out of Stock', 
     (int) 1 => 'Cars/Ford/Explorer' 
    ), 
    (int) 5 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars/Chevy/Cobalt' 
    ), 
    (int) 6 => array(
     (int) 0 => 'In Stock', 
     (int) 1 => 'Cars/Nissan' 
    ) 

); 
$output=array(); 
foreach ($cars as $car) { 
    foreach ($stocks as $stock) { 
    if(in_array($car, explode('/', $stock[1]))){ 
     $output[$car]=$stock[0]; 
     break; 
     }else{$output[$car]='Do not care';} 
} 
} 
echo '<pre>'; 
print_r($output); 

這將打印：

Array 
(
    [Maza] => Do not care 
    [Nissan] => In Stock 
    [Tacoma] => In stock 
    [Cobalt] => In Stock 
    [Explorer] => Out of Stock 
) 

Answer 2

也許

$Array1 = array("Maza", "Nissan","Tacoma","Cobalt","Explorer"); 
$secondarray = array(
    array('In Stock', 'Cars'), 
    array('In stock', 'Cars/Toyota/Tacoma'), 
    array('Out of Stock', 'Cars/Toyota/Celica'), 
    array('In Stock', 'Cars/Ford/Explorer'), 
    array('Out of Stock', 'Cars/Ford/Explorer'), 
    array('In Stock', 'Cars/Chevy/Cobalt'), 
    array('In Stock', 'Cars/Nissan')); 
function findcar($car, $secondarray) { 
    for($c = 0; $c <= count($secondarray); $c++) { 
     if(strpos(strtolower($secondarray[$c][1]), strtolower($car)) > 0) { 
       return $secondarray[$c][0]; 
     } 
    } 
} 

echo findcar($Array1[1], $secondarray); 

這將打印出In Stock，如果汽車沒有被發現它只是沒有返回。