在mvc4我試圖從模型數據從視圖到控制器使用Jquery Ajax但現在不要這個代碼有什麼問題可以任何人在這個問題上幫助我。阿賈克斯崗位模型控制器行動
<script src="~/Scripts/jquery-1.8.2.js"></script>
<script src="~/Scripts/jquery-1.8.2.min.js"></script>
<script src="~/Scripts/jquery.validate.js"></script>
<script src="~/Scripts/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#save").click(function() {
$("#content").html("<b>Please Wait...</b>");
var dataObject = {
empid: 1,
EmployeeName: "rizwan",
Address: "lahore",
Country: "pakistan",
Salary: "35000.00",
DepartmentName: "Field"
}
$.ajax({
type: "POST",
url: "/Home/Index",
data: dataObject,
success: function (data)
{
$("#empname").val(''),
$("#empadd").val(''),
$("#empcountry").val(''),
$("#empsalary").val(''),
$("#empdeptname").val(''),
$("#content").html("<div class='success'>"+data+"</div>")
},
error: function (ehr)
{
$("#content").html("<div class='failed'>Error! Please try again</div>");
},
})
});
});
</script>
這是我的控制器操作的代碼誰只是接收對象的值,並保存到數據庫 問題是,我沒能在接收控制器動作側值。
請幫我.....
[HttpPost]
public ActionResult Index(userview dataObject)
{
department dept = new department();
employee emp = new employee();
string message = "";
try
{
emp.employeeName = dataObject.EmployeeName;
emp.address = dataObject.Address;
emp.country = dataObject.Country;
emp.salary = dataObject.Salary;
dept.departmentName = dataObject.DepartmentName;
db.employees.Add(emp);
db.departments.Add(dept);
db.SaveChanges();
}
catch(Exception ex)
{
message = "Error! Please try again";
}
if (Request.IsAjaxRequest())
{
return new JsonResult { Data = message, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}
ViewBag.message = message;
return View();
}
這是我的模型類
public class userview
{
public int empId { get; set; }
public string EmployeeName { get; set; }
public string Address { get; set; }
public string Country { get; set; }
public decimal Salary { get; set; }
public string DepartmentName { get; set; }
}
沒有關係,但不包括同一個文件的非最小和最小版本 –
您是否在瀏覽器控制檯中收到任何錯誤? –
當我們點擊保存按鈕時,控制器動作端沒有收到值,即使我排除了未定義的文件,我只保留一個縮小版本文件 – user3780510