重用Python中的路徑

Question

我有一個代碼，以搜索和打開文件：

def OpenButton(self, event): 
    filedialog = wx.FileDialog(self, message = 'Open text file', 
     defaultDir = '.', 
     defaultFile = 'TestTOC.txt', 
     wildcard = "Text source (*.txt)|*.txt|" "All files (*.*)|*.*", 
     style = wx.OPEN) 
    if filedialog.ShowModal() == wx.ID_OK: 
     print filedialog.GetPath() 
    event.Skip() 

，它會告訴我該文件的路徑：C:\....\Desktop\test.txt

，我有需要另一個代碼讀取我選擇的文件：

def ReadButton(self, event): 
    file=open('C:....\Desktop\test.txt','r') # the same path as above 
    text=file.read() 
    file.close() 

如何複製該路徑並將其替換爲開放（....，'r'）？

Answer 1

使用變量？

def OpenButton(self, event): 
     filedialog = wx.FileDialog(self, message = 'Open text file', 
      defaultDir = '.', 
      defaultFile = 'TestTOC.txt', 
      wildcard = "Text source (*.txt)|*.txt|" "All files (*.*)|*.*", 
      style = wx.OPEN) 
     if filedialog.ShowModal() == wx.ID_OK: 
      self.filepath = filedialog.GetPath() 
     event.Skip() 

    def ReadButton(self, event): 
     file=open(self.filepath,'r') # the same path as above 
     text=file.read() 
     file.close() 

Answer 2

變化

print filedialog.GetPath() 

到

path = filedialog.GetPath() 
print path 

然後做任何你想要的路徑變量。