<!-- content -->
<article id="content" class="tabs">
<div class="wrapper">
<div class="box2">
<?php
//session_start();
$sql = "SELECT * FROM `db`.`news` ORDER BY `date` DESC LIMIT 20";
include 'php/dbconnection.php';
$conn = OpenCon(); //$conn=$_SESSION['conn'];
$result = mysqli_query($conn,$sql);
if($result){
$rows = mysqli_fetch_array($result);
echo "<div class='wrapper tab-content'>";
echo "<section class='col1'>";
echo "<h4><span>" . $rows['date']. "</span> </h4>";
echo "<p class='pad_bot2'><strong>". $rows['title']. "
</strong></p>";
echo "<p class='pad_bot1'>".$rows['des'] ."</p>";
echo "</section>";
echo "</div>";
}
?>
</div>
</div>
</article>
<!-- /content-->
在這裏,我想,打印「新聞」從數據庫表中,但我無法打印任何東西網頁。 任何人都可以指出,這有什麼不對? 非常感謝您的幫助!
使連接到數據庫,SQL之前選擇。 –
是的,但沒有輸出 –