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如何使用ng-repeat指令獲取數組最後一個索引+ 1 動態Profile.addresses [2] .site_name如何獲取數組ng-last的最後索引
<tr ng-repeat="lines in array">
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].site_name ' name='site_name'>
</td>
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].street_address ' name='street_address'>
</td>
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].city ' name='city'>
</td>
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].state ' name='state'>
</td>
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].country ' name='country'>
</td>
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].zip_code ' name='zip_code'>
</td>
<td>
<input type="text" class="form-control" id="inputDefault" ng-model=' Profile.addresses[2].phone_number ' name='phone_number'>
</td>
</tr>
Profile.addresses {{$ last}}。site_name ??喜歡這個 ? –
@AdeelKhan - 喜歡這個'Profile.addresses [$ last] .site_name' – tymeJV
如何獲得最後的索引+1值? ng-model ='Profile.addresses [$ last + 1] .site_name像這樣不起作用 –