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我有我創建了一個表格的麻煩,並試圖通過重定向一個JavaScript方法,我稱之爲只要單擊提交按鈕其他數據某處。的Joomla & JS;從形式將數據發送到控制器
正在發生的第一件事情,就是形式創建並填寫,然後用戶會點擊HTML生成的按鈕,這個動作在裏面:
onclick="javascript:saveEssayScore(<?php echo $key . "," . $pid; ?>);"
其次,腳本文件是隻讀並執行。該代碼是下面:
<script type="text/javascript" language="javascript">
document.body.className = document.body.className.replace("modal", "");
function saveEssayScore(key, pid){
var user_id = document.getElementById("user-"+key).value;
console.log("user " + user_id);
var grade = document.getElementById("grade-"+key).value;
console.log("grade " + grade);
var teacher_answer = document.getElementById("feedback-"+key).value;
console.log("teacher_answer " + teacher_answer);
var question_id = document.getElementById("question-"+key).value;
console.log("question_id " + question_id);
var quiz_id = document.getElementById("quiz-"+key).value;
console.log("quiz_id " + quiz_id);
var req = new Request.HTML({
method: 'post',
url: "<?php echo JURI::base();?>index.php?option=com_guru&controller=guruAuthor&task=saveFeedback&tmpl=component&format=raw",
data: { 'pid' : pid, 'user_id' : user_id, 'grade' : grade, 'teacher_answer' : teacher_answer, 'question_id' : question_id, 'quiz_id' : quiz_id},
onSuccess: function(response, responseElements, responseHTML){
alert('yeyy');
}
}).send();
}
現在,在URL,它被讀取,以運行在控制器guruAuthor
這是在部件com_guru
方法(任務)saveFeedback()
。
我遇到的問題是,我怎麼看,我只是通過HTML請求發送數據?我想這樣的東西$user_id = JRequest::getVar("user_id");
但每當我試圖呼應或轉儲,它將返回給我,但空。這並不是說我在JavaScript console.log(user_id);