無法解析android中的getInstance方法

-1

我正在關注一些教程，無法在getInstance中解決此錯誤。請幫助無法解析android中的getInstance方法

import android.support.annotation.Nullable; 
import android.support.v4.app.Fragment; 
import android.support.v4.app.FragmentManager; 
import android.support.v4.app.FragmentPagerAdapter; 
import android.support.v4.view.ViewPager; 
import android.support.v7.app.AppCompatActivity; 
import android.os.Bundle; 
import android.support.v7.widget.Toolbar; 
import android.view.LayoutInflater; 
import android.view.View; 
import android.view.ViewGroup; 
import android.widget.TextView; 

import com.example.s.foodapp.SlidingTab.SlidingTabLayout; 

public class MainActivity extends AppCompatActivity { 
private Toolbar toolbar; 
private ViewPager mPager; 
private SlidingTabLayout mTabs; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    toolbar= (Toolbar)findViewById(R.id.app_bar); 
    setSupportActionBar(toolbar); 
    getSupportActionBar().setDisplayHomeAsUpEnabled(true); 
    mPager=(ViewPager)findViewById(R.id.pager); 
    mTabs=(SlidingTabLayout)findViewById(R.id.tab); 
    mPager.setAdapter(new MyPagerAdapter(getSupportFragmentManager())); 
    mTabs.setViewPager(mPager); 

} 
class MyPagerAdapter extends FragmentPagerAdapter{ 
    String[] tabs; 
    public MyPagerAdapter(FragmentManager fm) { 
     super(fm); 
     tabs= getResources().getStringArray(R.array.tabs); 
    } 

    @Override 
    public Fragment getItem(int position) { 
     MyFragment myFragment= MyFragment.getInstance(position);// cannot resolve get instance 
     return myFragment; 
    } 

    @Override 
    public CharSequence getPageTitle(int position) { 
     return tabs[position]; 
    } 

    @Override 
    public int getCount() { 
     return 3; 
    } 
} 
public static class MyFragment extends Fragment{ 
    private TextView textView; 
    public static MyFragment.getInstance(int position){// cannot resolve get instance 
     MyFragment myFragment= new MyFragment(); 
     Bundle args=new Bundle(); 
     args.putInt("position",position); 
     myFragment.setArguments(args); 
     return myFragment; 
    } 
    @Override 
    public View onCreateView(LayoutInflater layoutInflater, @Nullable ViewGroup container,@Nullable Bundle savedInstanceState){ 
     View view= layoutInflater.inflate(R.layout.fragment_my,container,false); 
     textView= (TextView)view.findViewById(R.id.position); 
     Bundle bundle=getArguments(); 
     if(bundle!=null){ 
      textView.setText("The page selected is "+bundle.getInt("position")); 
     } 
     return view; 
    } 


}

}

這是在MainActivity文件。在教程中，這工作正常，當我嘗試它時，它給了我錯誤。

來源

2016-06-14 Saransh Agarwal

爲什麼在公共靜態MyFragment.getInstance（）中有一個點？ – GPuschka

我也沒有明白這一點。 https://www.youtube.com/watch?v=Fl0xMuo10yA –

這裏是教程的鏈接 –

只是取代這種方法。在方法聲明中不使用「。」

public static MyFragment getInstance(int position){// cannot resolve get instance 
     MyFragment myFragment= new MyFragment(); 
     Bundle args=new Bundle(); 
     args.putInt("position",position); 
     myFragment.setArguments(args); 
     return myFragment; 
    }

來源

2016-06-14 07:18:48

請勿使用'。'。您正在嘗試編寫一個返回片段實例的靜態方法。所以像這樣使用。

public static MyFragment getInstance(int position) 
{ 
     MyFragment myFragment= new MyFragment(); 
     Bundle args=new Bundle(); 
     args.putInt("position",position); 
     myFragment.setArguments(args); 
     return myFragment; 
}

來源

2016-06-14 07:27:34

無法解析android中的getInstance方法

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