基於持久性的Remember-Me在Spring社交樣本中正常登錄

所以我想在Spring Social Showcase-Sec-XML示例中添加一個記住我的功能。所以我想讓它成爲一個基於持久性的記憶我，但是每當我將數據源添加到記憶我時，我都會遇到一個錯誤。基於持久性的Remember-Me在Spring社交樣本中正常登錄

這是我在security.xml文件

<http use-expressions="true"> 
    <!-- Authentication policy --> 
    <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?param.error=bad_credentials" /> 
    <logout logout-url="/signout" delete-cookies="JSESSIONID" /> 
    <intercept-url pattern="/favicon.ico" access="permitAll" /> 
    <intercept-url pattern="/resources/**" access="permitAll" /> 
    <intercept-url pattern="/auth/**" access="permitAll" /> 
    <intercept-url pattern="/signin/**" access="permitAll" /> 
    <intercept-url pattern="/signup/**" access="permitAll" /> 
    <intercept-url pattern="/disconnect/facebook" access="permitAll" /> 
    <intercept-url pattern="/**" access="isAuthenticated()" /> 
    <remember-me key="jbcpCalendar" 
       data-source-ref="dataSource"/> 

    <!-- Spring Social Security authentication filter --> 
    <custom-filter ref="socialAuthenticationFilter" before="PRE_AUTH_FILTER" /> 
</http>

這是socialAuthenticationFilter Bean，它竟然放棄錯誤代碼。

<bean id="socialAuthenticationFilter" class="org.springframework.social.security.SocialAuthenticationFilter" 
    c:_0-ref="authenticationManager" 
    c:_1-ref="userIdSource" 
    c:_2-ref="usersConnectionRepository" 
    c:_3-ref="connectionFactoryLocator" 
    p:signupUrl="/spring-social-showcase/signup" 
    p:rememberMeServices-ref="org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices#0" /> <!-- TODO: Figure out how to wire this without this name -->

這是出來的堆棧跟蹤）：

Cannot resolve reference to bean 'socialAuthenticationFilter' while setting 
constructor argument with key [2]; nested exception is 
org.springframework.beans.factory.BeanCreationException: 

Error creating bean with name 'socialAuthenticationFilter' 
defined in ServletContext resource [/WEB-INF/spring/social-security.xml]: Cannot 
resolve reference to bean 
'org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices#0' 
while setting bean property 'rememberMeServices'; nested exception is 
org.springframework.beans.factory.NoSuchBeanDefinitionException: 
No bean named 
'org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices#0' is defined

有沒有辦法讓它使用持久基於記得我當它是一個常規登錄？

來源

2013-05-31 Kenneth Truong

我想你必須把命名空間上配置RememberMeServices的一個別名：

<remember-me services-alias="toto" 
      key="jbcpCalendar" 
      data-source-ref="dataSource"/>

而且使用別名是指它在你socialAuthenticationFilter配置：

<bean id="socialAuthenticationFilter" class="org.springframework.social.security.SocialAuthenticationFilter" 
    c:_0-ref="authenticationManager" 
    c:_1-ref="userIdSource" 
    c:_2-ref="usersConnectionRepository" 
    c:_3-ref="connectionFactoryLocator" 
    p:signupUrl="/spring-social-showcase/signup" 
    p:rememberMeServices-ref="toto" />

來源

2013-06-03 19:25:09 baraber

基於持久性的Remember-Me在Spring社交樣本中正常登錄

回答

相關問題