將動態表的計數總和作爲列MYSQL

以下mysql查詢將在每個用戶名後輸出一列用戶名和一系列5列，這些用戶名是5個計數的結果。將動態表的計數總和作爲列MYSQL

SELECT f.username, 
(SELECT COUNT(id) FROM sites s WHERE s.username = f.username) site_count, 
(SELECT COUNT(id) FROM banners b WHERE b.username = f.username) banner_count, 
(SELECT COUNT(id) FROM favorites fa WHERE fa.username = f.username) favorite_count, 
(SELECT COUNT(id) FROM social_posts so WHERE so.username = f.username) social_count, 
(SELECT COUNT(id) FROM stream_updates st WHERE st.username = f.username) stream_count 
FROM members f 
    WHERE f.username 
     IN (SELECT friend2 as username FROM list_friends WHERE friend1 = :user 
     AND friend2 <> :user) 
    OR f.username 
     IN (SELECT friend1 as username FROM list_friends WHERE friend2 = :user 
    AND friend1 <> :user) 
    OR f.username = :user

輸出示例：

| username | site_count | banner_count | favorite_count | social_count | stream_count | 
+----------+------------+--------------+----------------+--------------+--------------+ 
| user1 |  7  |  12  |  3  |  5  |  11  | 
| user2 |  2  |  1  |  12  |  1  |  0  | 
| user3 |  5  |  7  |  4  |  9  |  25  |

我所希望達到的結果是每一行的總和：

| username | site_count | banner_count | favorite_count | social_count | stream_count | 
+----------+------------+--------------+----------------+--------------+--------------+ 
|   | 14  |  20  |  19  |  15  |  36  |

來源

2016-09-30 Bruce

我的解決辦法是使用用戶定義的變量有：=，這樣的變量將與每個總和進行更新。

有關詳細信息閱讀：http://dev.mysql.com/doc/refman/5.7/en/user-variables.html

更新查詢的結束結果如下：

SELECT f.username, 
@sites := SUM((SELECT COUNT(*) FROM sites s WHERE s.username = f.username)) AS site_count, 
@banner := SUM((SELECT COUNT(*) FROM banners b WHERE b.username = f.username)) AS banner_count, 
@favs := SUM((SELECT COUNT(*) FROM favorites fa WHERE fa.username = f.username)) AS favorite_count, 
@social := SUM((SELECT COUNT(*) FROM social_posts so WHERE so.username = f.username)) AS social_count, 
@stream := SUM((SELECT COUNT(*) FROM stream_updates st WHERE st.username = f.username)) AS stream_count 
    FROM members f 
    WHERE f.username 
    IN (SELECT friend2 as username FROM list_friends WHERE friend1 = :user 
    AND friend2 <> :user) 
    OR f.username 
    IN (SELECT friend1 as username FROM list_friends WHERE friend2 = :user 
    AND friend1 <> :user) 
    OR f.username = :user

來源

2016-10-01 01:34:08 Bruce

只是增加了一筆算？

SELECT f.username, 
    SUM((SELECT COUNT(id) FROM sites s WHERE s.username = f.username)) site_count, 
    SUM((SELECT COUNT(id) FROM banners b WHERE b.username = f.username)) banner_count, 
    SUM((SELECT COUNT(id) FROM favorites fa WHERE fa.username = f.username)) favorite_count, 
    SUM((SELECT COUNT(id) FROM social_posts so WHERE so.username = f.username)) social_count, 
    SUM((SELECT COUNT(id) FROM stream_updates st WHERE st.username = f.username)) stream_count 
FROM members f 
WHERE f.username 
    IN (SELECT friend2 as username FROM list_friends WHERE friend1 = :user 
    AND friend2 <> :user) 
OR f.username 
    IN (SELECT friend1 as username FROM list_friends WHERE friend2 = :user 
AND friend1 <> :user) 
OR f.username = :user

如果需要每個用戶的數量，只是添加Group By f.username到底

來源

2016-09-30 09:46:28

可惜只是包裝他們SUM不會削減它，我希望它是那麼簡單。這將花費每個用戶的每個計數的總和，這是毫無用處的。例如，如果用戶1的計數返回5，則執行5的總和不會改變結果。由於IN語句中的f.username和用戶名不同，因此group by將無法工作，因此無法如此分組。我試圖通過f.username來做一個組，也嘗試了按用戶名分組，所有結果都沒有改變。 – Bruce

好吧，然後..可能是簡單的方法來做到這一點是計數出來的sql.if使用PHP只是在PHP計數他們 –

這可能實際上是路要走，但我希望基於SQL的解決方案，因爲我必須反正爲數據建立連接，並且所有的數據都被索引，所以我想盡可能在mysql中完成。 :) – Bruce

將動態表的計數總和作爲列MYSQL

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