Android HTTP GET錯誤

對不起，我是新來的世界上的java和android。我想了解爲什麼它總是響應錯誤。謝謝！Android HTTP GET錯誤

try { 
      HttpClient client = new DefaultHttpClient(); 
      String getURL = "http://www.google.com"; 
      HttpGet get = new HttpGet(getURL); 
      HttpResponse responseGet = client.execute(get); 
      HttpEntity resEntityGet = responseGet.getEntity(); 
      if (resEntityGet != null) { 
      Toast.makeText(getApplicationContext(), "ok", Toast.LENGTH_LONG).show(); 
      } 
    } catch (Exception e) { 
     //e.printStackTrace(); 
     Toast.makeText(getApplicationContext(), "error", Toast.LENGTH_LONG).show(); 
    }

進口

import org.apache.http.HttpEntity; 
import org.apache.http.HttpResponse; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.methods.HttpGet; 
import org.apache.http.impl.client.DefaultHttpClient;

，是的，我進入許可互聯網

<?xml version="1.0" encoding="utf-8"?> 
<manifest xmlns:android="http://schemas.android.com/apk/res/android" 
    package="com.example.testhttp" 
    android:versionCode="1" 
    android:versionName="1.0" > 

     <uses-permission android:name="android.permission.INTERNET" /> 

    <uses-sdk 
     android:minSdkVersion="8" 
     android:targetSdkVersion="17" />

來源

2013-07-14 Valkyrie00

使用logcat的檢查你的「錯誤」相關的Java堆棧跟蹤。如果您不瞭解堆棧跟蹤，請編輯您的問題並將其發佈到此處。 – CommonsWare

取消註釋'e.printStackTrace（）'並查看logcat中的異常 – Navid777

請參閱http://stackoverflow.com/questions/22395417/error-strictmodeandroidblockguardpolicy-onnetwork – user4805969

似乎是像你正試圖使在UI線程的http請求。

把你的請求放在另一個線程中。

來源

2013-07-14 17:03:07

@ user2068102刪除Toast.makeText（getApplicationContext（），「確定「，Toast.LENGTH_LONG）.show（）;從try塊和catch塊並使用Log.d（「OK」，「Ok」）;在try和catch塊中，並在logCat中查看結果！ –

如果你想使用吐司不是用它爲：runOnUiThread（新的Runnable（）{ @覆蓋公共無效的run（）{ Toast.makeText（.....）顯示（）;} }）; –

@ user2068102歡迎:) –

您也可以使用這個代碼，以使一個HTTP請求：

public class RequestClient extends AsyncTask<String, Void, String>{ 
     Context context; 

     public RequestClient(Context c) { 
      context = c; 
     } 

     @Override 
     protected void onPreExecute() { 
      super.onPreExecute(); 
     } 

     @Override 
     protected String doInBackground(String... aurl){ 
     String responseString=""; 
     HttpClient client = null; 
     try { 
      client = new DefaultHttpClient(); 
      HttpGet get = new HttpGet(LoginActivity.url); 
      HttpResponse responseGet = client.execute(get); 
      HttpEntity resEntityGet = responseGet.getEntity(); 
      if (resEntityGet != null) { 
       responseString = EntityUtils.toString(resEntityGet); 
       Log.i("GET RESPONSE", responseString.trim()); 
      } 
     } catch (Exception e) { 
      Log.d("ANDRO_ASYNC_ERROR", "Error is "+e.toString()); 
     } 
      Log.d("ANDRO_ASYNC_RESPONSE", responseString.trim()); 
      client.getConnectionManager().shutdown(); 
     return responseString.trim(); 

     } 


     @Override 
     protected void onPostExecute(String response) { 
      super.onPostExecute(response); 
      } 
    }

來源

2013-07-17 12:37:10

Android HTTP GET錯誤

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