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我正嘗試通過代理服務器訪問網站。我正在使用httpclient。動態獲取代理服務器詳細信息時SOCKS服務器的格式錯誤
這是工作正常的代碼：
import org.apache.commons.httpclient.Credentials;
import org.apache.commons.httpclient.HostConfiguration;
import org.apache.commons.httpclient.HttpClient;
import org.apache.commons.httpclient.HttpMethod;
import org.apache.commons.httpclient.HttpStatus;
import org.apache.commons.httpclient.UsernamePasswordCredentials;
import org.apache.commons.httpclient.auth.AuthScope;
import org.apache.commons.httpclient.methods.GetMethod;
import java.io.IOException;
import java.net.InetSocketAddress;
import java.net.Proxy;
import java.net.ProxySelector;
import java.net.URI;
import java.net.URISyntaxException;
import java.util.Properties;
public class Working {
private static String PROXY_HOST = "proxy.test.org";
private static int PROXY_PORT = 80;
public static void main(String[] args) {
HttpClient client = new HttpClient();
HttpMethod method = new GetMethod("https://www.example.org");
HostConfiguration config = client.getHostConfiguration();
config.setProxy(PROXY_HOST, PROXY_PORT);
try {
client.executeMethod(method);
if (method.getStatusCode() == HttpStatus.SC_OK) {
String response = method.getResponseBodyAsString();
System.out.println("Response = " + response);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
method.releaseConnection();
}
System.out.println("end");
}
}
但是當我使用下面的方法來設置proxy_host使用和proxy_port使用值動態我正在「從SOCKS服務器畸形的答覆」異常
public static void getProxyDetails()
{
Properties systemSettings = System.getProperties();
systemSettings.put("proxySet", "true");
try {
Proxy proxy = (Proxy) ProxySelector.getDefault().select(new URI(
"https://www.example2.com/xyz")).iterator().
next();
System.out.println("proxy hostname : " + proxy.type());
InetSocketAddress addr = (InetSocketAddress)proxy.address();
if (addr == null) {
System.out.println("No Proxy");
} else {
System.out.println("proxy hostname : " + addr.getHostName());
System.out.println("proxy port : " + addr.getPort());
PROXY_HOST = addr.getHostName();
PROXY_PORT = addr.getPort();
}
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
我嘗試了本網站提供的其他建議，但沒有解決我的問題。 我在代碼中犯了什麼錯誤？任何幫助表示讚賞。