在while循環中計數/隨機int

Question

我想要while循環來改變每次迭代的數字（count和random int），但是當我運行程序時，循環只會繼續計數上的相同數字，隨機INT：

# if 4 sides 
die1 = random.randint(1,4) 
die2 = random.randint(1,4) 
count = 1 

while sides == 4 and die1 != die2: 
    print (count, ". die number 1 is", die1, "and die number 2 is", die2,".") 
    count == count + 1 

print ("You got snake eyes! Finally! On try number", count,".") 

Answer 1

您還需要做while循環內的random電話，否則他們將不會改變。另一件事是，你比較==，而不是設置=計數器：

import random 

sides = 4 
count = 1 
die1 = random.randint(1,4) 
die2 = random.randint(1,4) 

while sides == 4 and die1 != die2: 
    print (count, ". die number 1 is", die1, "and die number 2 is", die2,".") 
    count += 1 
    die1 = random.randint(1,4) 
    die2 = random.randint(1,4) 

print ("You got snake eyes! Finally! On try number", count,".") 

試圖測試運行給我：

1 . die number 1 is 4 and die number 2 is 3 . 
2 . die number 1 is 2 and die number 2 is 1 . 
3 . die number 1 is 1 and die number 2 is 2 . 
4 . die number 1 is 3 and die number 2 is 4 . 
5 . die number 1 is 1 and die number 2 is 4 . 
You got snake eyes! Finally! On try number 6 . 

一種選擇，這幾乎是相同的，但在使用break而不是條件while循環將是：

import random 

sides = 4 
count = 1 

def tossdie(): 
    """Function to create a random integer for a die""" 
    return random.randint(1,4) 

while True: 
    die1 = tossdie() 
    die2 = tossdie() 
    print (count, ". die number 1 is", die1, "and die number 2 is", die2,".") 
    if die1 == die2: 
     break 
    count += 1 

print ("You got snake eyes! Finally! On try number", count,".") 

Answer 2

每次電話random.randint(1,4)，要創建一個隨機數的時間。無論何時打印，它都不會奇蹟般地變爲新的隨機數。

在您的while循環內生成新的隨機數字random.randint(1, 4)。

第二個問題是count == count + 1檢查是否相等（並在您的情況下返回False）。要執行分配，請使用賦值運算符=或count += 1將count加1。

如果你想要一臺發電機是無休止地吐出隨機數，寫一個：

>>> import random 
>>> def rng(i, j): 
...  while True: 
...   yield random.randint(i, j) 
... 
>>> random_gen = rng(1, 4) 
>>> next(random_gen) 
2 
>>> next(random_gen) 
3 
>>> next(random_gen) 
2 
>>> next(random_gen) 
2 
>>> next(random_gen) 
1 

Answer 3

不知道爲什麼你需要sides變量，所以我離開它出。 您想要在每個循環中滾動模具，這意味着您必須在每個循環中將die1和die2重新分配爲隨機數。

import random 

# Initial parameters 
die1 = random.randint(1,4) 
die2 = random.randint(1,4) 
count = 1 

# Loop and roll die each time 
while die1 != die2: 
    print(count, ". die number 1 is", die1, "and die number 2 is", die2,".") 
    die1 = random.randint(1,4) 
    die2 = random.randint(1,4) 
    count += 1 

# Print on which die roll you got two equal die numbers rolled 
print ("You got snake eyes! Finally! On try number", count,".") 

Answer 4

您可以使用一個for循環與iter吐出來對隨機數，enumerate會做計數，對蛇的眼睛，你也應該檢查這兩者都是1不是一個隨機匹配對：

from random import randint                 

def repeating_rand(i, j):                  
    for count, (r1, r2) in enumerate(iter(lambda: (randint(i, j), randint(i, j)), None), 1): 
     if r1 == 1 and r2 == 1:                
      return "You got snake eyes! Finally! On try number {}.".format(count)    
     print("Try no. {}, die number 1 is {} and die number 2 is {}".format(count, r1, r2)) 

輸出：

In [12]: repeating_rand(1, 4) 
Try no. 1, die number 1 is 1 and die number 2 is 2 
Try no. 2, die number 1 is 4 and die number 2 is 1 
Try no. 3, die number 1 is 1 and die number 2 is 2 
Try no. 4, die number 1 is 1 and die number 2 is 3 
Try no. 5, die number 1 is 1 and die number 2 is 3 
Try no. 6, die number 1 is 3 and die number 2 is 4 
Try no. 7, die number 1 is 4 and die number 2 is 2 
Try no. 8, die number 1 is 1 and die number 2 is 2 
Try no. 9, die number 1 is 3 and die number 2 is 2 
Try no. 10, die number 1 is 4 and die number 2 is 3 
Try no. 11, die number 1 is 1 and die number 2 is 3 
Try no. 12, die number 1 is 3 and die number 2 is 4 
Out[12]: 'You got snake eyes! Finally! On try number 13.'