我得到的錯誤,當我嘗試創建ContestantInfo *contestantStructArray = new ContestantInfo [numberOfContestants];
動態結構陣列錯誤
繼承人我的代碼「不完全類型的分配」:
#include <fstream>
#include <iostream>
using namespace std;
struct ContestantInfo;
int main()
{
//opens all the files for input and output
fstream contestantsFile("contestants.txt", ios::in);
fstream answerKeyFile("answers.txt", ios::in);
fstream reportFile("report.txt", ios::out);
//used to determine how many contestants are in the file
int numberOfContestants = 0;
string temp;
//checks to see if the files opened correctly
if(contestantsFile.is_open() && answerKeyFile.is_open() && reportFile.is_open()){
//counts the number of lines in contestants.txt
while(getline(contestantsFile, temp, '\n')){
numberOfContestants++;
}
//Puts the read point of the file back at the beginning
contestantsFile.clear();
contestantsFile.seekg(0, contestantsFile.beg);
//dynamic array that holds all the contestants ids
string *contestantIDNumbers = new string [numberOfContestants];
//Reads from the contestants file and initilise the array
for(int i = 0; i < numberOfContestants; i++){
getline(contestantsFile, temp, ' ');
*(contestantIDNumbers + i) = temp;
//skips the read point to the next id
contestantsFile.ignore(256, '\n');
}
ContestantInfo *contestantStructArray = new ContestantInfo [numberOfContestants];
}
else
{
cout << "ERROR could not open file!" << endl;
return 0;
}
}
struct ContestantInfo{
string ID;
float score;
char *contestantAnswers;
int *questionsMissed;
};
內Struct ContestantInfo
的指針最終應該指向動態數組以及如果改變任何東西。我是一名學生,所以如果我正在做一些愚蠢的事情,請不要猶豫。
好吧我粗略瞭解那篇文章。你能提出一個包含可以解決這個問題的代碼,或者創建一個像這樣的動態結構數組只是不起作用嗎? –
@FinnWilliams當然,你只需要把結構定義放在main之前。 – cnelmortimer
愚蠢簡單的修復謝謝你。 –