我發現了以下bash的CGI工作示例。如果我改變前兩行帶CGI的shell腳本可以與bash一起使用,但不能與sh
#!/bin/sh
echo "Content-type: text/html\n\n"
以下腳本停止工作,當我瀏覽這個腳本在瀏覽器中的「富」,「酒吧」和「foobar的」底部宣佈的腳本消失。
任何想法我怎麼能使用sh來做同樣的例子。其實我需要通過嵌入式設備運行這樣一個例子,我沒有bash,但sh。
#!/bin/bash
echo -e "Content-type: text/html\n\n"
echo "
<html>
<body>
<form action="http://${HTTP_HOST}:${SERVER_PORT}${SCRIPT_NAME}?foo=1234" method="POST">
<input type="text" name="bar">
<textarea name="foobar"></textarea>
<input type="submit">
</form>"
# (internal) routine to store POST data
cgi_get_POST_vars()
{
# check content type
# FIXME: not sure if we could handle uploads with this..
[ "${CONTENT_TYPE}" != "application/x-www-form-urlencoded" ] && \
echo "Warning: you should probably use MIME type "\
"application/x-www-form-urlencoded!" 1>&2
# save POST variables (only first time this is called)
[ -z "$QUERY_STRING_POST" \
-a "$REQUEST_METHOD" = "POST" -a ! -z "$CONTENT_LENGTH" ] && \
read -n $CONTENT_LENGTH QUERY_STRING_POST
return
}
# (internal) routine to decode urlencoded strings
cgi_decodevar()
{
[ $# -ne 1 ] && return
local v t h
# replace all + with whitespace and append %%
t="${1//+/ }%%"
while [ ${#t} -gt 0 -a "${t}" != "%" ]; do
v="${v}${t%%\%*}" # digest up to the first %
t="${t#*%}" # remove digested part
# decode if there is anything to decode and if not at end of string
if [ ${#t} -gt 0 -a "${t}" != "%" ]; then
h=${t:0:2} # save first two chars
t="${t:2}" # remove these
v="${v}"`echo -e \\\\x${h}` # convert hex to special char
fi
done
# return decoded string
echo "${v}"
return
}
# routine to get variables from http requests
# usage: cgi_getvars method varname1 [.. varnameN]
# method is either GET or POST or BOTH
# the magic varible name ALL gets everything
cgi_getvars()
{
[ $# -lt 2 ] && return
local q p k v s
# get query
case $1 in
GET)
[ ! -z "${QUERY_STRING}" ] && q="${QUERY_STRING}&"
;;
POST)
cgi_get_POST_vars
[ ! -z "${QUERY_STRING_POST}" ] && q="${QUERY_STRING_POST}&"
;;
BOTH)
[ ! -z "${QUERY_STRING}" ] && q="${QUERY_STRING}&"
cgi_get_POST_vars
[ ! -z "${QUERY_STRING_POST}" ] && q="${q}${QUERY_STRING_POST}&"
;;
esac
shift
s=" $* "
# parse the query data
while [ ! -z "$q" ]; do
p="${q%%&*}" # get first part of query string
k="${p%%=*}" # get the key (variable name) from it
v="${p#*=}" # get the value from it
q="${q#$p&*}" # strip first part from query string
# decode and evaluate var if requested
[ "$1" = "ALL" -o "${s/ $k /}" != "$s" ] && \
eval "$k=\"`cgi_decodevar \"$v\"`\""
done
return
}
# register all GET and POST variables
cgi_getvars BOTH ALL
echo "<pre>foo=$foo</pre>"
echo "<pre>bar=$bar</pre>"
echo "<pre>foobar=$foobar</pre>"
echo "</body>
</html>"
更新1: sh -x script
返回如下:
+ echo Content-type: text/html\n\n
Content-type: text/html
+ echo
<html>
<body>
<form action=http://:?foo=1234 method=POST>
<input type=text name=bar>
<textarea name=foobar></textarea>
<input type=submit>
</form>
<html>
<body>
<form action=http://:?foo=1234 method=POST>
<input type=text name=bar>
<textarea name=foobar></textarea>
<input type=submit>
</form>
+ cgi_getvars BOTH ALL
+ [ 2 -lt 2 ]
+ local q p k v s
+ [ ! -z ]
+ cgi_get_POST_vars
+ [ != application/x-www-form-urlencoded ]
+ echo Warning: you should probably use MIME type application/x-www-form-urlencoded!
Warning: you should probably use MIME type application/x-www-form-urlencoded!
+ [ -z -a = POST -a ! -z ]
+ return
+ [ ! -z ]
+ shift
+ s= ALL
+ [ ! -z ]
+ return
+ echo <pre>foo=</pre>
<pre>foo=</pre>
+ echo <pre>bar=</pre>
<pre>bar=</pre>
+ echo <pre>foobar=</pre>
<pre>foobar=</pre>
+ echo </body>
</html>
</body>
</html>
'/ bin/sh'仍然是某種shell,你需要在做任何改變之前確定它。 「sh --version」說什麼? –
@baltusaj您是否嘗試在調試模式下運行腳本?你可以通過運行'sh -x scriptname.sh'來完成。將'sha-bang'行更改爲'Bourne Shell'並在調試模式下運行。它可能會拋出一些有用的信息。 –
/bin/sh --version,sh --verion返回'sh:非法操作 - '錯誤。如果在sh shell中運行它,會發生相同的錯誤。我通過在默認bash shell中運行/ bin/sh來執行sh shell。 – baltoro