返回特定成員下的所有級別

Question

以下我希望返回成員Engineering下的所有樹。
我在猜我在濫用IS？
我應該使用membervalue嗎？
我想用特定的成員會更有效率？

WITH 
    MEMBER [Measures].[LevelName] AS 
     [Employee].[Employee Department].Level.Name 
    MEMBER [Measures].[LevelNumber] AS 
     [Employee].[Employee Department].Level.Ordinal 
SELECT 
    { 
    FILTER(
     [Employee].[Employee Department].AllMembers, 
     [Employee].[Employee Department].[Department] IS 
      [Employee].[Employee Department].[Department].&[Engineering] 
     ) 
    } ON 1, 
    { 
    [Measures].[LevelName], 
    [Measures].[LevelNumber] 
    } ON 0 
FROM [Adventure Works] 

以下是錯誤消息：

執行查詢...查詢（10，3）是函數期望爲2參數的水平 表達。成員表達式被使用。執行 完成

Answer 1

您不需要使用FILTER函數來獲取屬於特定成員的所有子成員。剛做這樣的事情，而不是：

SELECT 
{ 
    [Employee].[Employee Department].[Department].&[Engineering].CHILDREN 
} ON 1, 
... 

如果你想下面的特定成員的整個樹，用後人功能：

SELECT 
{ 
    DESCENDANTS([Employee].[Employee Department].[Department].&[Engineering], 
     [Employee].[Employee Department].[Department], AFTER) 
} ON 1, 
...