模擬輸入JavaScript

我試圖模擬在JavaScript在一個特定TextArea。代碼：模擬輸入JavaScript

function enter1() { 
     var keyboardEvent = document.createEvent('KeyboardEvent'); 
     var initMethod = typeof keyboardEvent.initKeyboardEvent !== 'undefined' ? 'initKeyboardEvent' : 'initKeyEvent'; 
     keyboardEvent[initMethod]('keydown', // event type : keydown, keyup, keypress 
      true, // bubbles 
      true, // cancelable 
      window, // viewArg: should be window 
      false, // ctrlKeyArg 
      false, // altKeyArg 
      false, // shiftKeyArg 
      false, // metaKeyArg 
      13, // keyCodeArg : unsigned long the virtual key code, else 0 
      13 // charCodeArgs : unsigned long the Unicode character associated with the depressed key, else 0 
     ); 
     document.getElementById('text').dispatchEvent(keyboardEvent); 
}

TextArea：

<textarea id="text"> </textarea>

當我打電話ENTER1（）什麼都不幹的textarea的。爲什麼？

來源

2015-05-02 Luca Laiton

[這裏]（http://stackoverflow.com/questions/961532/firing-a-keyboard-event-in-javascript），[這裏]（http://stackoverflow.com/questions/10455626/keydown-simulation-in-chrome-fires-normally-but-the-the-correct-key） – AvrilAlejandro

@avrilalejandro感謝艾薇兒的支持，但是每個功能都沒有通過「回車」。我不明白。 –

我認爲這是一個瀏覽器bug，因爲keyboardEvent.which是不可寫的。爲了解決這個問題，你必須在分配鍵碼之前刪除keyboardEvent.which屬性。

function enter1() { 
    var keyboardEvent = document.createEvent('KeyboardEvent'); 
    delete keyboardEvent.which; 
    var initMethod = typeof keyboardEvent.initKeyboardEvent !== 'undefined' ? 'initKeyboardEvent' : 'initKeyEvent'; 
    keyboardEvent[initMethod](
    'keydown', // event type : keydown, keyup, keypress 
    true, // bubbles 
    true, // cancelable 
    window, // viewArg: should be window 
    false, // ctrlKeyArg 
    false, // altKeyArg 
    false, // shiftKeyArg 
    false, // metaKeyArg 
    13, // keyCodeArg : unsigned long the virtual key code, else 0 
    13 // charCodeArgs : unsigned long the Unicode character associated with the depressed key, else 0 
    ); 
    document.getElementById('text').dispatchEvent(keyboardEvent); 
}

另一種解決方案是KeyboardEvent Constructor。只要注意兼容性問題。

function enter1() { 
    var keyboardEvent = new KeyboardEvent('keydown'); 
    delete keyboardEvent.which; 
    keyboardEvent.which = 13; 
    document.getElementById('text').dispatchEvent(keyboardEvent); 
}

來源

2015-05-02 15:13:46 Lewis

我編輯的代碼，但沒有改變。感謝您的回答。 –

@LucaLaiton您可以嘗試手動分配'keyboardEvent.which = 13;'而不是將鍵碼傳遞給'initMethod'。 – Lewis

 function premi_enter() { var keyboardEvent = document.createEvent('KeyboardEvent'); delete keyboardEvent.which; keyboardEvent.which = 13; document.getElementById('text').dispatchEvent(keyboardEvent); }

–

模擬輸入JavaScript

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