得到URL和非法字符下載的文件路徑

Question

string uri = "https://sometest.com/l/admin/ical.html?t=TD61C7NibbV0m5bnDqYC_q"; 

    string filePath = "D:\\Data\\Name"; 

    WebClient webClient = new WebClient(); 
    webClient.DownloadFile(uri, (filePath + "/" + uri.Substring(uri.LastIndexOf('/')))); 

/// filePath + "/" + uri.Substring(uri.LastIndexOf('/')) = "D:\\Data\\Name//ical.html?t=TD61C7NibbV0m5bnDqYC_q" 

Accesing整個（串）uri，一個的.iCal文件將被自動下載...的文件名room113558101.ics（不，這將幫助）。

如何正確獲取文件？

Answer 1

您正在以錯誤的方式構建文件路徑，導致文件名無效（ical.html?t=TD61C7NibbV0m5bnDqYC_q）。相反，使用Uri.Segments屬性，並使用路徑段（這將是在這種情況下ical.html另外，不要用手合併文件路徑 - 使用Path.Combine：

var uri = new Uri("https://sometest.com/l/admin/ical.html?t=TD61C7NibbV0m5bnDqYC_q"); 
var lastSegment = uri.Segments[uri.Segments.Length - 1]; 
string directory = "D:\\Data\\Name"; 
string filePath = Path.Combine(directory, lastSegment); 
WebClient webClient = new WebClient(); 
webClient.DownloadFile(uri, filePath); 

回答您關於得到正確的文件名編輯的問題。在這種情況下，你不知道正確的文件名，直到您對服務器的請求，並得到響應文件名會被包含在響應的Content-Disposition頭所以，你應該做的是這樣的：。

var uri = new Uri("https://sometest.com/l/admin/ical.html?t=TD61C7NibbV0m5bnDqYC_q"); 
string directory = "D:\\Data\\Name"; 
WebClient webClient = new WebClient(); 
// make a request to server with `OpenRead`. This will fetch response headers but will not read whole response into memory   
using (var stream = webClient.OpenRead(uri)) { 
    // get and parse Content-Disposition header if any 
    var cdRaw = webClient.ResponseHeaders["Content-Disposition"]; 
    string filePath; 
    if (!String.IsNullOrWhiteSpace(cdRaw)) { 
     filePath = Path.Combine(directory, new System.Net.Mime.ContentDisposition(cdRaw).FileName); 
    } 
    else { 
     // if no such header - fallback to previous way 
     filePath = Path.Combine(directory, uri.Segments[uri.Segments.Length - 1]); 
    } 
    // copy response stream to target file 
    using (var fs = File.Create(filePath)) { 
     stream.CopyTo(fs); 
    } 
}