1
我有一個腳本工作,我可以打開文件,如果我通過文件名,但現在文件數量增加,並沒有意義必須在每個文件上運行腳本個別。所以我決定讓python讀取目錄中的al文件。Python XLRD沒有這樣的文件或目錄
for root, dirs, files in os.walk("Approved_LRPMP_Worksheets/"):
for fyle in files:
if fyle.endswith(".xlsx"):
print fyle
book = xlrd.open_workbook(fyle)
print "book opened"
的輸出是這樣的:
I found a file: Agoura Hills LRPMP Review Sheet.xlsx
Traceback (most recent call last):
File "test.py", line 21, in <module>
book = xlrd.open_workbook(fyle)
File "/Library/Python/2.7/site-packages/xlrd/__init__.py", line 394, in open_workbook
f = open(filename, "rb")
IOError: [Errno 2] No such file or directory: 'Agoura Hills LRPMP Review Sheet.xlsx'
該文件清楚地讀取,文件的名稱是在命令行之前,我得到了錯誤的輸出。我覺得這很簡單,我應該趕上,但它已經逃避了我最後30分鐘...