我需要你的幫助。這是我的程序的源代碼。我需要了解分數1,分數2,分數3和分數4函數的操作。需要幫助拆卸
1 #include <stdio.h>
2 #include <string.h>
3 #include <stdlib.h>
4 #include <sys/types.h>
5 #include <sys/stat.h>
6 #include <pwd.h>
7 #include <unistd.h>
8
9 #include "score.h"
10
(gdb)
11 int main(int argc, char *argv[])
12 {
13 int i, j, k, l, s;
14 struct passwd *pw;
15 char cmd[1024];
16
17 /* Make sure that we have exactly 5 arguments: the name of the executable, and 4 numbers */
18 if (argc != 5) {
19 printf("Usage: %s i j k l\n where i,j,k,l are integers.\n Try to get as high a score as you can.\n", argv[0]);
20 exit(8);
(gdb)
21 }
22
23 initialize();
24
25 /* Convert the inputs to ints */
26 i = atoi(argv[1]);
27 j = atoi(argv[2]);
28 k = atoi(argv[3]);
29 l = atoi(argv[4]);
30
(gdb)
31 printf("You entered the integers %d, %d, %d, and %d.\n", i, j, k, l);
32 s = score1(i) + score2(j) + score3(k) + score4(l);
33
34 printf("Your score is %d.\n", s);
35 if (s > 0) {
36 pw = getpwuid(getuid());
37
38 printf("Thank you!\n");
40 system(cmd);
我已經開始拆解類似下面的代碼:
(gdb) disas score1
Dump of assembler code for function score1:
0x080488b0 <score1+0>: push %ebp
0x080488b1 <score1+1>: mov %esp,%ebp
0x080488b3 <score1+3>: cmpl $0xe1e4,0x8(%ebp)
0x080488ba <score1+10>: setne %al
0x080488bd <score1+13>: movzbl %al,%eax
0x080488c0 <score1+16>: sub $0x1,%eax
0x080488c3 <score1+19>: and $0xa,%eax
0x080488c6 <score1+22>: pop %ebp
0x080488c7 <score1+23>: ret
(gdb) disas score2
Dump of assembler code for function score2:
0x080488c8 <score2+0>: push %ebp
0x080488c9 <score2+1>: mov %esp,%ebp
0x080488cb <score2+3>: mov 0x8049f88,%eax
0x080488d0 <score2+8>: sub $0x2,%eax
0x080488d3 <score2+11>: mov %eax,0x8049f88
0x080488d8 <score2+16>: cmp 0x8(%ebp),%eax
0x080488db <score2+19>: setne %al
0x080488de <score2+22>: movzbl %al,%eax
0x080488e1 <score2+25>: sub $0x1,%eax
0x080488e4 <score2+28>: and $0xa,%eax
0x080488e7 <score2+31>: pop %ebp
0x080488e8 <score2+32>: ret
(gdb) disas score3
Dump of assembler code for function score3:
0x080488e9 <score3+0>: push %ebp
0x080488ea <score3+1>: mov %esp,%ebp
0x080488ec <score3+3>: mov 0x8(%ebp),%eax
0x080488ef <score3+6>: and $0xf,%eax
0x080488f2 <score3+9>: mov 0x8048e00(,%eax,4),%eax
0x080488f9 <score3+16>: pop %ebp
0x080488fa <score3+17>: ret
(gdb) disas score4
Dump of assembler code for function score4:
0x080488fb <score4+0>: push %ebp
0x080488fc <score4+1>: mov %esp,%ebp
0x080488fe <score4+3>: push %ebx
0x080488ff <score4+4>: mov 0x8(%ebp),%eax
0x08048902 <score4+7>: movzwl %ax,%edx
0x08048905 <score4+10>: mov %eax,%ecx
0x08048907 <score4+12>: shr $0x10,%ecx
0x0804890a <score4+15>: lea 0x0(,%edx,8),%eax
0x08048911 <score4+22>: sub %edx,%eax
0x08048913 <score4+24>: cmp %ecx,%eax
0x08048915 <score4+26>: jne 0x8048920 <score4+37>
0x08048917 <score4+28>: mov $0x8000ffff,%ebx
0x0804891c <score4+33>: test %edx,%ecx
0x0804891e <score4+35>: jne 0x8048940 <score4+69>
0x08048920 <score4+37>: mov %ecx,%eax
0x08048922 <score4+39>: xor %edx,%eax
0x08048924 <score4+41>: cmp $0xf00f,%eax
0x08048929 <score4+46>: jne 0x804893b <score4+64>
0x0804892b <score4+48>: mov %ecx,%eax
0x0804892d <score4+50>: or %edx,%eax
0x0804892f <score4+52>: mov $0xa,%ebx
0x08048934 <score4+57>: cmp $0xf42f,%eax
---Type <return> to continue, or q <return> to quit---
0x08048939 <score4+62>: je 0x8048940 <score4+69>
0x0804893b <score4+64>: mov $0x0,%ebx
0x08048940 <score4+69>: mov %ebx,%eax
0x08048942 <score4+71>: pop %ebx
0x08048943 <score4+72>: pop %ebp
0x08048944 <score4+73>: ret
我已經開始檢查score2。 我所做的是:
(
gdb) x 0x8049f88
0x8049f88 <secret>: "Чй"
(gdb) disas 0x8049f88
Dump of assembler code for function secret:
0x08049f88 <secret+0>: dec %dl
0x08049f8a <secret+2>: add %al,(%eax)
End of assembler dump.
而且我在這裏失去了
這是我認爲到目前爲止情況(見註釋):
(gdb) disas score2
Dump of assembler code for function score2:
0x080488c8 <score2+0>: push %ebp
0x080488c9 <score2+1>: mov %esp,%ebp 'Copy %esp into %ebp
0x080488cb <score2+3>: mov 0x8049f88,%eax 'executing: decrement and add
0x080488d0 <score2+8>: sub $0x2,%eax ' subtract $0x2 from %eax (How can I figure out what $0x2
0x080488d3 <score2+11>: mov %eax,0x8049f88 'Have no idea what this does
0x080488d8 <score2+16>: cmp 0x8(%ebp),%eax compare of %ebp to %eax (why %ebp has 0x8 preceding it?)
0x080488db <score2+19>: setne %al 'I have no idea what this does
0x080488de <score2+22>: movzbl %al,%eax
0x080488e1 <score2+25>: sub $0x1,%eax
0x080488e4 <score2+28>: and $0xa,%eax
0x080488e7 <score2+31>: pop %ebp
0x080488e8 <score2+32>: ret
如果你可以幫助我理解score2對一個整數執行什麼類型的轉換,以及我可以在gdb中運行哪些命令來幫助我,我真的很感激它,並會嘗試重新計算我自己也是(得分1-3)。我只是迷失在這裏。
您似乎沒有發佈這些函數的源代碼......另外,如果您對'score2'感興趣,爲什麼還要發佈其他所有函數的反彙編程序? –
如果您想查看編譯器將生成的內容,請使用'-S'開關運行gcc,以使用'-O0'生成彙編代碼以禁用優化。以此作爲指導(或作爲替代)。 –
[示例代碼](http://sscce.org/)應該是完整的,簡潔和可編輯的。樣本不完整,gdb輸出的文物(行號和提示)阻止了它的編譯。請通過編輯您的問題來清理示例代碼。另外,請選擇[有意義的名稱](http://tinyurl.com/so-hints)。 – outis