我無法立即捕捉到StaleStateException，爲什麼？

Question

我無法立即捕捉到RuntimeException的StaleStateException，爲什麼？爲什麼設計這個？

如果第一個事務沒有提交，我不會趕上例外，但StaleStateException延伸的RuntimeException，疑問，它應該應該抓住它立即

public ResponseInfo catchExce() { 

    try { 
     throwExceServiceA.throwExce(); 
    } catch (StaleStateException e) { 
     System.out.println("This is a StaleStateException"); 
    } catch (Exception e) { 
     System.out.println("This is a StaleStateException. Also is catched here"); 
    } finally { 
     System.out.println("This block is always executed"); 
    } 

} 

ThrowExceServiceA

@Transactional(propagation = Propagation.REQUIRES_NEW) 
public void throwExce() throws InterruptedException { 

    throwExceServiceB.throwExce(); 
    Thread.sleep(1000); 
} 

ThrowExceServiceB

@Transactional(propagation = Propagation.REQUIRES_NEW) 
public void throwExce() { 
    throw new StaleStateException(""); 
} 

Answer 1

將此代碼添加到您的代碼：

public ResponseInfo catchExce() { 

    try { 
     throwExceServiceA.throwExce(); 
    } 
    catch (StaleStateException e) { 
     System.out.println("This is a StaleStateException"); 
    } 
    catch (Exception e) { 
     System.out.println("This is a StaleStateException. Also is catched here"); 
    } 
    finally{ 
     System.out.println("This block is always executed"); 
    } 
} 

我希望這個澄清一點您的演示