我在哪裏犯錯？

-5

這是一門學校工作，用於製作計算區域和周長的程序編譯器/語法錯誤「預計;在void之前」和「void void之前的預期主表達式」。我不知道問題是否在頭文件中。我在哪裏犯錯？

#include"shape.h" 
#include<iostream> 
using namespace std; 


Shapes::Shapes()//base class 
    {status=true;} 

    void Shapes::launch() 
     {cout<<"Which figure are we working on ?"<<endl; 
     cout<<"Square(1),Triangle(2),Rectangle(3);"<<endl; 
     cout<<"Circle(4) or regular polygons(5)"<<endl; 
     cin>>a;} 

    void Shapes::aime()//mistake here. 
     {    //switch to decide shape 
     if (status) switch(a){ 
     case'1':{Square::Square() 
     void Square::readSide()//mistake too. 
     {cout<<"The length of one side in metres : \t"; 
     cin>>side;} 
    void Square::getsPerimeter()//another mistake. 
     {cout<<"The perimeter is "<<(side*4)<<" metres."<<endl;} 
     void Square::getsArea(){cout<<"The Area is "<<(side*side)<<" squared 
     metres."<<endl;}//again. 
     } 


case'2':{Triangle::Triangle() 
    void Triangle::readData()//mistake 
    {cout<<"The length of the base in metres : \t"; 
    cin>>base; 
    cout<<"The length of the height in metres : \t"; 
    cin>>height;} 
    void Triangle::gettArea()//error 
    {cout<<"The Area is "<<(height*base/2)<<endl;} 
    } 

case'3':{Rectangle::Rectangle() 
void Rectangle::readDatar()//error 
{cout<<"The length in metres : \t"; 
cin>>length; 
cout<<"The width in metres : \t"; 
cin>>width;} 
void Rectangle::getrArea()//error 
{cout<<"Area is "<<(length*width)<<" squared metres."<<endl;} 
void Rectangle::getrPerimeter() 
{cout<<"Perimeter is "<<(2*(length+width))<<" metres."<<endl;} 
} 

case'4':{Circle::Circle() 
void Circle::readRadius(){cout<<"The length of the radius in metres : \t"; 
cin>>radius;} 
void Circle::getCirc()//error 
{cout<<"Circumference is "<<(2*3.14159*radius)<<" metres."<<endl;} 
Circle::getcArea()//error 
{cout<<"Area is "<<(radius*radius*3.14159)<<" squared metres."<<endl;} 
} 


case'5':{Polygon::Polygon() 
void Polygon::readDatap(){cout<<"The number of sides : \t";//error 
cin>>num; 
cout<<"The length of one side in metres : \t"; 
cin>>pside; 
cout<<"The length of the apothem in metres : \t"; 
cin>>apothem;} 
void Polygon::getpPerimeter()//error 
{cout<<"The perimeter is "<<(num*pside)<<" metres."<<endl;} 
void Polygon::getpArea()//another error 
{cout<<"The area is "<<(num*pside*apothem/2)<<" squared metres."<<endl;} 
} 
} //switch() terminated 
} //aime() terminated 
bool Shapes::run(){return status;} 
//to keep the app open 
//the classes are derived classes of the base class:Shapes

來源

2017-04-12 Czar

您好，歡迎StackOverflow上。請編輯您的問題以提供[最小化，完整和可驗證]（http://stackoverflow.com/help/mcve）示例來說明您的問題。 –

請編輯您的代碼，並以更好的方式縮進它。如果您希望我們提供幫助，您還應該嘗試在最小代碼示例中重現您的錯誤。 – OutOfBound

我很確定這個錯誤包含一個行號。 – YSC

你定義功能的開關語句，它根本就沒有用C++允許內（除lambda表達式/函子，但他們另一次的主題）。

您需要定義switch語句之外的函數，然後從那裏調用它們。下面是你在做什麼的例子（這是錯誤）：

#include <iostream> 

int main(int argc, char** argv) { 
    switch(argc) { 
    case 1: 
     void example(){ std::cout<< "The number of sides : \t"; } 
     break; 
    } 
}

這是你需要做什麼：

#include <iostream> 

void example() { std::cout<< "The number of sides : \t"; } 

int main(int argc, char** argv) { 
    switch(argc) { 
    case 1: 
     example(); 
     break; 
    } 
}

來源

2017-04-12 11:05:16 OMGtechy

我在哪裏犯錯？

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