php參數傳輸

Question

我嘗試從我的應用程序發送一些文本到PHP，但不知何故，我從來沒有收到文本。這裏有什麼不對？

NSString *name = [[NSString alloc]initWithString: @"Hello World"]; 
NSString *email = [[NSString alloc]initWithString: @"Ohai2u"]; 
NSString *urlString = [NSString stringWithFormat:@"http://www.myhosturlxyz.com/tracktxt.php?name=%@ email=%@", 
         [name stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding], 
         [email stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; 

NSURL *url = [[NSURL alloc] initWithString:urlString]; 

NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url]; 

NSData *urlData; 
NSURLResponse *response; 
urlData = [NSURLConnection sendSynchronousRequest:urlRequest returningResponse:&response error:nil]; 
[url release]; 

我所做的PHP是

<?php 
    $name = $_REQUEST['name']; 
    $email = $_REQUEST['email']; 
    $myFile = "tracktxtf.txt"; 
    $fh = fopen($myFile, 'a') or die("can't open file"); 
    fwrite($fh, "my posted var is " .$name $email "\n"); 
    fclose($fh); 
?> 

Answer 1

只是胡亂猜測，但你可能需要name=%@和email=%a之間&，使之name=%@&email=%@？

或者，您可以嘗試使用$_GET['name']和$_GET['email']而不是REQUEST嗎？也許嘗試寫入print_r($_REQUEST, true); print_r($_GET, true);到您的調試文件，並看看它包含什麼。