嗨,我正在製作披薩項目,並希望用戶只挑一個基地,所以一旦他說是的稀將不會有問題的厚基地。披薩項目厚或薄
System.out.print("\nDo you want thick base?");
input = keyboard.nextLine();
choice = input.charAt(0);
if (choice == 'y'){
pizza.setPizzaBase(new PizzaBase("thick"));
}
//Thin base
System.out.print("\nDo you want thin base?");
input = keyboard.nextLine();
choice = input.charAt(0);
if (choice == 'y') {
pizza.setPizzaBase(new PizzaBase("thin"));
}
只是使用'else' ... – Blub
不是JavaScript。 – nderscore
將鍵盤監聽邏輯提取到它自己的類中可能會更好嗎? –