分組要素按日期

Question

我有以下代碼：

for($j=0; $j<=odbc_fetch_row($result); $j++){ 


        $date = odbc_result($result, 'DATE'); 
        $A = odbc_result($result, 'A'); 
        $B = odbc_result($result, 'B'); 
        $C = odbc_result($result, 'C'); 
        $D = odbc_result($result, 'D'); 
        $E= odbc_result($result, 'E'); 

        echo $date." ".$A." ".$B." ".$C." ".$D." ".$E."<br/>"; 
} 

DATE A B C D E 
20140101 0 8225.12 0 0 0 
20140101 18483.28 0 0 0 0 
20140101 0 0 12275.49 0 0 
20140101 0 0 0 3013.50 0 
20140101 0 0 0 0 4552.20 
20140102 0 3612.30 0 0 0 
20140102 6850.10 0 0 0 0 
20140102 0 0 5695.45 0 0 
20140102 0 0 0 3291.80 0 
20140102 0 0 0 0 2006.20 
20140103 0 2684.10 0 0 0 
20140103 13342.26 0 0 0 0 
20140103 0 0 6981.14 0 0 
20140103 0 0 0 3887.93 0 
20140103 0 0 0 0 5117.50 

我如何通過組類似下面的日期的元素？

DATE ABCDE

20140101 18483.28 8225.12 12275.49 3013.50 4552.20
20140102 6850.10 3612.30 5695.45 3291.80 2006.20

Answer 1

你可以做到這一點在MySQL查詢直接如下假設你的數據模式是相同的意思爲每行中a，b，c，d，e中的任意一列將具有一個值並且全部爲0，因爲

SELECT `date`, 
     max(`a`) as `a`, 
     max(`b`) as `b`, 
     max(`c`) as `c`, 
     max(`d`) as `d`, 
     max(`e`) as `e` 
FROM `test` 
GROUP BY `date` 

所以執行查詢後，您可以通過循環獲取數據

檢查這裏

http://sqlfiddle.com/#!2/4952f0/12

Answer 2

嘗試

$result = array(); 
for($j=0; $j<=odbc_fetch_row($result); $j++){ 
     $date = odbc_result($result, 'DATE'); 
     $A = odbc_result($result, 'A'); 
     $B = odbc_result($result, 'B'); 
     $C = odbc_result($result, 'C'); 
     $D = odbc_result($result, 'D'); 
     $E= odbc_result($result, 'E'); 
     $row = array($date,$A,$B,$C,$D,$E); 
     for($i=0;$i<count($row);$i++){ 
     if($row[$i]>0) { 
      $result[$date][$i] = $row[$i]; 
     } 
     } 
} 

觀看演示here