我應該如何設計表格以將標籤存儲在數據庫中？

Question

"question_id": 58640 
"tags": ["polls", "fun", "quotes"] 
"title": "Great programming quotes" 
"question_id": 184618 
"tags": ["polls", "fun", "comment"] 
"title": "What is the best comment in source code you have ever encountered?" 
"question_id": 3734102 
"tags": ["c++", "linux", "exit-code"] 
"title": "Why cant' I return bigger values from main function ?" 
"question_id": 2349378 
"tags": ["communication", "terminology", "vocabulary"] 
"title": "New programming jargon you coined?" 
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"tags": ["open-source", "project-management", "failure", "fail"] 
"title": "How to make an open source project fail" 
"question_id": 3699150 
"tags": ["testing", "interview-questions", "job-interview"] 
"title": "Interview question please help" 

這只是一個文本提取一些問題，我得到了使用SO API。

要使此查詢成爲可能，我想使用SQLite來存儲數據。

我應該如何存儲標籤列？

由於這裏的限制，以便爲五個標籤，我可以使用五個標籤1，標籤2 ... ...，但我認爲會有什麼可以做的更優雅。可以擴展到任何數量的標籤在那裏，而且還可以處理基本的查詢，如

select title from table where tag has "c++" and "boost" but not "c" 

Answer 1

某事，這是一個多對多的關係：問題有多個標籤，標籤可以出現在多個問題。這意味着您必須創建三個表格，一個用於問題，一個用於標籤，另一個用於這些表格之間的鏈接。生成的查詢應該是這樣的：

SELECT title FROM question 
     INNER JOIN question_tag_link USING (question_id) 
     INNER JOIN tag USING (tag_id) 
      WHERE tag_name IN('c++', 'boost') 
       AND NOT EXISTS(
      SELECT * FROM tag t1 
      WHERE t1.tag_name = 'c' 
       AND t1.question_id = question.question_id); 

不是那麼簡單，但我認爲這是要付出，如果你不想被限制做的價格。如果少於64個不同的標籤，你可以使用SET字段類型，但是你會失去很大的靈活性（很難添加新的標籤）。

Answer 2

select distinct a.QuestionTitle 
from 
(
select q.QuestionID, QuestionTitle, TagName 
from QuestionTags as x 
join Question  as q on q.QuestionID = x.QuestionID 
join Tag   as t on t.TagID  = x.TagID 
where TagName in ('c++', 'boost') 
) as a 
left join 
(
select q.QuestionID, QuestionTitle, TagName 
from QuestionTags as x 
join Question  as q on q.QuestionID = x.QuestionID 
join Tag   as t on t.TagID  = x.TagID 
where TagName = 'c' 
) as b on b.QuestionID = a.QuestionID 
where b.QuestionTitle is null 
order by a.QuestionTitle ;