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如何在不使用Hibernate類的情況下在JPA中映射Map?JPA Map <String,String []>映射
public Map<String, String[]> parameters = new HashMap<String, String[]>();
在此先感謝。
如何在不使用Hibernate類的情況下在JPA中映射Map?JPA Map <String,String []>映射
public Map<String, String[]> parameters = new HashMap<String, String[]>();
在此先感謝。
示例實現:
@Entity
@Table(name = "MAP") //optional
public class Parameters {
@Id
@Column(name = "\"KEY\"") //optional
private String id;
@ElementCollection
@CollectionTable(//optional
name = "MAP_VALUES",
joinColumns = { @JoinColumn(name="MAP_KEY") }
)
private Collection<String> collection;
public Parameters() { }
public Parameters(String key, Collection<String> values) {
this.id = key;
this.collection = values;
}
public Collection<String> values() {
return collection;
}
// ...
}
實體實例可以插入到數據庫中,如下所示:
em.persist(new Parameters("first", Arrays.asList("a", "b", "c")));
em.persist(new Parameters("second", Arrays.asList("d", "e", "f")));
...
這將產生在數據庫中兩個表:
MAP MAP_VALUES
KEY MAP_KEY COLLECTION
------ ------- ----------
first first a
second first b
second c
second d
MAP_KEY
第th列e MAP_VALUES
表是外鍵,是指MAP
表。
內容可如下獲得:
Parameters entry = em.find(Parameters.class, "second");
List<String> values = entry.values();
...
或
String query = "SELECT p FROM Parameters p";
List<Parameters> entries = em.createQuery(query, Parameters.class)
.getResultList();
List<String> values = entry.values();
...