2013-04-15 25 views
1

我無法在TriggerIO插件中維護實例,因此我需要一種靜態方式來響應我的AVAudioPlayer的事件。但是,我不能將player.delegate設置爲audio_API,所以我有點卡住了。將類用作AVAudioPlayerDelegate用於靜態AVAudioPlayer

audio_API.h:

@interface audio_API : NSObject<AVAudioPlayerDelegate> 

audio_API.m:

static AVAudioPlayer* player = nil; 


@implementation audio_API 


+ (void)play:(ForgeTask*)task { 

    // parse the file url from the file object 
    ForgeFile* file = [[ForgeFile alloc] initWithFile:[task.params objectForKey:@"file"]]; 
    NSString* fileURL = [file url]; 

    NSLog(@"Playing file at %@", fileURL); 

    NSURL* url = [NSURL URLWithString:fileURL]; 


    // TESTING 
    url = [[NSBundle mainBundle] URLForResource:@"seconds.m4a" withExtension:nil]; 
    // END TESTING 

    NSAssert(url, @"URL is invalid."); 

    // create the player 
    NSError* error = nil; 
    player = [[AVAudioPlayer alloc] initWithContentsOfURL:url error:&error]; 
    if(!player) 
    { 
     NSLog(@"Error creating player: %@", error); 
    }; 

// player.delegate = audio_API; 

    [player play]; 

    [task success:nil]; 
} 


+ (void)audioPlayerDidFinishPlaying:(AVAudioPlayer *)player successfully:(BOOL)flag 
{ 
    if (flag) { 
     [ForgeLog d:@"Audio finished playing successfully."]; 
    } else { 
     [ForgeLog d:@"Audio did not finish playing successfully."]; 
    } 

    // call the audio.finishedPlaying event 
    [[ForgeApp sharedApp] event:@"audio.finishedPlaying" withParam:nil]; 
} 

+ (void)audioPlayerDecodeErrorDidOccur:(AVAudioPlayer *)player error:(NSError *)error 
{ 
    [ForgeLog d:@"Audio had error decoding."]; 
    [ForgeLog e:error]; 

    // call the audio.decodeErrorOccurred event 
    [[ForgeApp sharedApp] event:@"audio.decodeErrorOccurred" withParam:nil]; 
} 

@end 

如何使這項工作任何想法?

謝謝。

+0

當您嘗試設置委託時,有什麼問題? –

+0

'/Users/gsquare567/forge-workspace/plugins/audio/inspector/ios-inspector/ForgeModule/alert/audio_API.m:47:23:意外的接口名稱'audio_API':預期的表達式'當我嘗試'player.delegate = audio_API;' – Garrett

回答

3

委託必須是一個對象,但audio_API是類型名稱。但是,你可以簡單地分配委託是audio_API類對象:

player.delegate = (id<AVAudioPlayerDelegate>)[audio_API class]; 

注意:如果你不投的類對象,編譯器會抱怨,因爲[audio_API class]返回Class,而不是一個Class<AVAudioPlayerDelegate>,甚至如果您在界面上指定代理人audio_API