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我想爲我創建一些幫助工具。因爲我創建了一個交易agregator，我需要將xpath放入我的數據庫，但是需要創建一些工具來幫助我進行驗證。Xpath和HTML表單動作發佈php
我有一個HTML文件，我需要投入的XPath，然後用我的行動去generatingxpath.php文件，我需要看看我得到使用XPath我寫的。 所以...
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<form name="form1" method="post" action="generatingxpath.php">
<p>
<label for="websource"></label>
Web source:
<input name="websource" type="text" id="websource" size="70">
is:</p>
<p>
<label for="links"></label>
Links:
<input name="links" type="text" id="links" size="77">
OK!
</p>
<p>
<label for="title"></label>
Title:
<input name="title" type="text" id="title" size="78">
is:</p>
<p>
<label for="image"></label>
Image:
<input name="image" type="text" id="image" size="76">
show:</p>
<p>
<label for="disscount"></label>
Disscount:
<input name="disscount" type="text" id="disscount" size="72">
is:</p>
<p>
<label for="price"></label>
Price:
<input name="price" type="text" id="price" size="77">
is:</p>
<p>
<label for="description"></label>
Desription:
<input name="desription" type="text" id="description" size="72">
is:</p>
<p>
<label for="coordinates"></label>
Coordinates:
<input name="coordinates" type="text" id="coordinates" size="70">
lat,lng is:</p>
<p>
<input type="submit" name="Submit" id="Submit" value="Preview">
or
<input type="submit" name="Add to database" id="Add to database" value="Add To Database">
</p>
<p> </p>
</form>
</body>
</html>
和我的PHP文件是：
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>GENERATING XPATH</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
<?php
function curl($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_ENCODING, "gzip");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
libxml_use_internal_errors(true);
$websource = $_POST["websource"];
$links = $_POST["links"];
$title = $_POST["title"];
$image = $_POST["image"];
$disscount = $_POST["disscount"];
$price = $_POST["price"];
$description = $_POST["description"];
$coordinates = $_POST["coordinates"];
//start generating xpath script
$dom = new DOMDocument();
@$dom->loadHTMLFile($websource);
$xpath = new DOMXPath($dom);
$entries = $xpath->query($links);
$output = array();
$i = 1;
foreach($entries as $e) {
$dom2 = new DOMDocument();
@$dom2->loadHTMLFile($websource . $e->textContent);
$xpath2 = new DOMXPath($dom2);
$data = array();
$data['websource']= ($websource . $e->textContent);
$data['title'] = trim($xpath2->query($title)->item(0)->textContent);
$data['description'] = trim($xpath2->query($description)->item(0)->textContent);
$data['image'] = trim($xpath2->query($image)->item(0)->textContent);
$string = $xpath2->query($coordintes)->item(1)->textContent;
preg_match_all('#(([0-9-]+){1,3}.([0-9]+))#is', $string, $matches);
$data['lat']=$matches[1];
$data['lng']=$matches[2];
$data['disscount'] = trim($xpath2->query($disscount)->item(0)->textContent);
$data['price'] = trim($xpath2->query($price)->item(0)->textContent);
//print to see that all is fine or need to change some xpath direction
echo $data['websource'];
echo $data['links'];
echo $data['title'];
echo $data['image'];
echo $data['disscount'];
echo $data['price'];
echo $data['lat'];
echo $data['lng'];
echo $data['description'];
$output[] = $data;
}
?>
</body>
</html>
我第一次拿到67線幾個錯誤。每個...等
是有一些簡單的解決方案我得到導致在同一頁上，所以要得到一些網站的文字使用XPath，但顯示HTML網頁... AJAX ???或者其他的東西？
什麼是我的問題的最佳解決方案？ 如何解決這個問題？
這個東西會很有趣，並會幫助很多人 –
所以當我點擊預覽時我需要從一些URL中提取文本，我輸入到基於xpath的文本文件中 –
非常對不起，我的英語，是非常糟糕的，但我努力改變，很快 –