從條件列表中隨機選擇 - Python

Question

我在列表中創建了一個笛卡爾積，現在我想隨機取出4個不同的元組（我試着在帖子結尾處）。

shape = ['triangle' , 'square' , 'circle' , 'cross'] 
color = ['green' , 'red' , 'blue' , 'pink'] 

__cartesianPsc__ = list(itertools.product(shape , color)) 

我的笛卡爾乘積

[('triangle', 'green'), ('triangle', 'red'), ('triangle', 'blue'), ('triangle', 'pink'), ('square', 'green'), ('square', 'red'), ('square', 'blue'), ('square', 'pink'), ('circle', 'green'), ('circle', 'red'), ('circle', 'blue'), ('circle', 'pink'), ('cross', 'green'), ('cross', 'red'), ('cross', 'blue'), ('cross', 'pink')] 

，現在我想打得到4個不同的元組隨機帶有三角形，正方形，圓形和跨和4種不同顏色綠，紅，粉，藍，但每顏色和各種形狀/顏色只有一個時間存在 實施例：

第一拾取

first = ('triangle', 'green') 
second = ('square', 'red') 
third = ('circle', 'blue') 
fourth = ('cross', 'pink') 

二

first = ('circle', 'blue') 
second = ('cross', 'red') 
third = ('triangle', 'pink') 
fourth = ('square', 'green') 

等

是否有人知道如何做到這一點？我嘗試了一個隨機循環random.range從三角形，正方形，圓形，十字形，但我不知道如何做到這一點，以獲得不同的顏色

--------我的舊Code- ---- 我有問題，它總是（三角形，綠色）作爲元組，但其他3個元組不同（每次）。

shape = ['triangle' , 'square' , 'circle' , 'cross'] 
color = ['green' , 'red' , 'blue' , 'pink'] 

__cartesianPsc__ = list(itertools.product(shape , color)) 


while True: 
    se1 = random.randrange(0, 4, 1) 
    se2 = random.randrange(5, 8, 1) 
    se3 = random.randrange(9, 12, 1) 
    se4 = random.randrange(13, 16, 1) 


# safe the randomly choosen tuple of the cartesian product 
    first = __cartesianPsc__[se1] #triangle X color 
    second = __cartesianPsc__[se2] # square X color 
    third = __cartesianPsc__[se3] #circle X color 
    fourth = __cartesianPsc__[se4] #cross X color 


    # if statement to stop the While-LOOP only if there are 4 tuples with 
    # 4 different shapes and colors ! 
    """Problem: (triangle, green) is always a tuple, no other color with triangle 
    if second[1] != first[1] and second[1] != third[1] and second[1] != fourth[1] \ 
    and third[1] != first[1] and third[1] != second[1] and third[1] != fourth[1] \ 
    and fourth[1] != first[1] and fourth[1] != second[1] and fourth[1] != third[1] \ 
    and first[1] != second[1] and first[1] != third[1] and first[1] != fourth[1]: 
    """ 
break 

問候馬丁:)

Answer 1

擴展我的評論：根本不要創建笛卡爾產品。只需洗牌兩種形狀和顏色，並zip他們。我必須做幾次才能在列表的第一位獲得與'triangle'不同的形狀，但這只是隨機的。

>>> import random 
>>> shape = ['triangle' , 'square' , 'circle' , 'cross'] 
>>> color = ['green' , 'red' , 'blue' , 'pink'] 
>>> random.shuffle(shape) 
>>> random.shuffle(color) 
>>> list(zip(shape, color)) 
[('triangle', 'green'), ('cross', 'pink'), ('circle', 'red'), ('square', 'blue')] 
>>> random.shuffle(color) 
>>> random.shuffle(shape) 
>>> list(zip(shape, color)) 
[('triangle', 'red'), ('cross', 'blue'), ('square', 'green'), ('circle', 'pink')] 
>>> random.shuffle(color) 
>>> random.shuffle(shape) 
>>> list(zip(shape, color)) 
[('triangle', 'blue'), ('circle', 'green'), ('cross', 'red'), ('square', 'pink')] 
>>> random.shuffle(shape) 
>>> random.shuffle(color) 
>>> list(zip(shape, color)) 
[('triangle', 'pink'), ('cross', 'green'), ('square', 'red'), ('circle', 'blue')] 
>>> random.shuffle(shape) 
>>> random.shuffle(color) 
>>> list(zip(shape, color)) 
[('triangle', 'green'), ('square', 'pink'), ('cross', 'red'), ('circle', 'blue')] 
>>> random.shuffle(shape) 
>>> random.shuffle(color) 
>>> list(zip(shape, color)) 
[('cross', 'green'), ('square', 'red'), ('circle', 'blue'), ('triangle', 'pink')] 

Answer 2

這應該這樣做：

import random 
def get4Random(): 
    shape = ['triangle' , 'square' , 'circle' , 'cross'] 
    color = ['green' , 'red' , 'blue' , 'pink'] 
    random.shuffle(shape) 
    random.shuffle(color) 
    return zip(shape, color) 

隨機混合每個列表，然後壓縮洗牌後的值。