如何通過類名獲取類類型？

Question

namespace Myspace 
{ 
    public class MyClass 
    { 
    } 
} //This class is in another file. 

using Myspace; 
static void Main(string[] args) 
{ 
    Regex regexViewModelKey = new Regex(RegularExpr.ViewModelKeyPattern); 
    string viewModel = regexViewModelKey.Match(match.Value).Value; 
    //Now, vieModel is a string, and its value is "MyClass". So, I only know the class name, this is why I ask this question. 

    //Now, I'm only allowed to use the string form of this class name to get its type. 
    //I have tyied like this, but its no use. 
    Type t = Type.GetType(viewModel); 
    //it's return a null. 

    //Then I tyied another method like this, but there is an exception when calling Assembly.Load 
    Assembly assembly = Assembly.Load("Myspace"); 
    Type ty = assembly.GetType("Myspace" + viewModel); 
} 

我希望我的問題很清楚。任何人都可以幫助我.THX 我只允許使用這個類名的字符串形式來獲得它的類型。

thx everyone。 我已經自己解決了這個問題。

{ 
     Type t = Type.GetType(string.Concat(viewModel, ",", "Myspace")); 
} 

Answer 1

一般來說，除非您使用反射或界面進行操作，否則幾乎不需要進行類型比較。儘管如此：

如果你知道你要進行對比的類型，使用的是或作爲運營商：

if(unknownObject is TypeIKnow) { // run code here 

as運算符執行的是返回null鑄造如果失敗，而不是一個例外：

TypeIKnow typed = unknownObject as TypeIKnow; 

如果你不知道的類型，只是想運行時類型信息，使用.GetType（）方法：

Type typeInformation = unknownObject.GetType(); 



    // int is a value type 
    int i = 0; 
    // Prints True for any value of i 
    Console.WriteLine(i.GetType() == typeof(int)); 

    // string is a sealed reference type 
    string s = "Foo"; 
    // Prints True for any value of s 
    Console.WriteLine(s == null || s.GetType() == typeof(string)); 

    // object is an unsealed reference type 
    object o = new FileInfo("C:\\f.txt"); 
    // Prints False, but could be true for some values of o 
    Console.WriteLine(o == null || o.GetType() == typeof(object)); 

// Get the type of a specified class. 
       Type myType1 = Type.GetType("System.Int32"); 
       Console.WriteLine("The full name is {0}.", myType1.FullName); 
       // Since NoneSuch does not exist in this assembly, GetType throws a TypeLoadException. 
       Type myType2 = Type.GetType("NoneSuch", true); 
       Console.WriteLine("The full name is {0}.", myType2.FullName); 

    // FileSystemInfo is an abstract type 
    FileSystemInfo fsi = new DirectoryInfo("C:\\"); 
    // Prints False for all non-null values of fsi 
    Console.WriteLine(fsi == null || fsi.GetType() == typeof(FileSystemInfo)); 

Answer 2

如果使用完全限定的類名稱（包括它的名稱空間），則Type.GetType（model）行可以工作。另外，如果它與調用的代碼位於不同的程序集中，則當引用的程序集對象是包含該類型的程序集的實例時，應該使用Assembly.GetType（typeName）。

Answer 3

只使用函數typeof（）。該參數就是那個類的名字。

Type type = typeof(FIXProtoClientTest); 

MSDN on typeof()