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我有幾個選擇元素:jQuery的selectMenu創建換行符(不能讓它顯示inline)
<div id="divReports">
<select id="ddlReportTypes" style="width:200px;"></select>
<select id="ddlReportFarms" style="width:200px;"></select>
<select id="ddlReportClusters" style="width:200px;"></select>
</div>
他們展示自己就好了,在同一條直線
,當我把他們成這樣selectMenus:
$("#divReports select").selectmenu({
style: 'dropdown',
transferClasses: true
});
他們拒絕成爲內聯,並且每一個佔據整個行 這是因爲看到的螢火的HTML:
<select id="ddlReportTypes" style="width: 200px; display: none;">
<a id="ddlReportTypes-button" class="ui-selectmenu ui-widget ui-state-default ui-selectmenu-dropdown ui-corner-all" aria-owns="ddlReportTypes-menu" aria-haspopup="true" href="#" role="button" style="width: 200px;">
<span class="ui-selectmenu-status">Traffic variance report </span>
<span class="ui-selectmenu-icon ui-icon ui-icon-triangle-1-s"></span>
</a>
<select id="ddlReportFarms" style="width: 200px; display: none;">
<a id="ddlReportFarms-button" class="ui-selectmenu ui-widget ui-state-default ui-corner-all ui-selectmenu-dropdown" aria-owns="ddlReportFarms-menu" aria-haspopup="true" href="#" role="button" style="width: 200px; display: block;">
<select id="ddlReportClusters" style="width: 200px; display: none;">
<a id="ddlReportClusters-button" class="ui-selectmenu ui-widget ui-state-default ui-corner-all ui-selectmenu-dropdown" aria-owns="ddlReportClusters-menu" aria-haspopup="true" href="#" role="button" style="width: 200px; display: block;">
我試過的風格=「顯示:內聯」,沒有工作.. 我做了標記顯示:內聯,但只有讓事情變得更糟..
任何想法嗎? 10X
你錯過報價'「'在第二和第三'select'元素'ST yle'屬性,更正它們並重新檢查 – thecodeparadox
感謝codeparadox,但是當我粘貼到這裏時,它是複製粘貼錯誤。我原來的代碼很好.. – Igal