playframework org.hibernate.PersistentObjectException：傳遞給持久化的分離實體：模型

我試圖用playframework 2.2與JPA和H2數據庫設置應用程序。我去了這一點： http://www.playframework.com/documentation/2.2.x/JavaJPA 和計算機數據庫JPA樣本項目playframework org.hibernate.PersistentObjectException：傳遞給持久化的分離實體：模型

我得到了一個錯誤：

org.hibernate.PersistentObjectException: detached entity passed to persist: models.

，當我跑我的項目我得到這個錯誤：

STACK TRACE

 --- (Running the application from SBT, auto-reloading is enabled) --- 

[info] play - Listening for HTTP on /0:0:0:0:0:0:0:0:8081 

(Server started, use Ctrl+D to stop and go back to the console...) 

[info] play - datasource [jdbc:h2:mem:SupraCIRS] bound to JNDI as DefaultDS 
[info] play - database [default] connected at jdbc:h2:mem:SupraCIRS 
[info] play - Application started (Dev) 
[error] play - Cannot invoke the action, eventually got an error: javax.persistence.PersistenceException: org.hibernate.PersistentObjectException: detached entity passed to persist: models.MedicalIncident 
[error] application - 

! @6gh420nj2 - Internal server error, for (POST) [/incydent_medyczny/zapisz] -> 

play.api.Application$$anon$1: Execution exception[[PersistenceException: org.hibernate.PersistentObjectException: detached entity passed to persist: models.MedicalIncident]] 
     at play.api.Application$class.handleError(Application.scala:293) ~[play_2.10.jar:2.2.1] 
     at play.api.DefaultApplication.handleError(Application.scala:399) [play_2.10.jar:2.2.1] 
     at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1] 
     at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1] 
     at scala.Option.map(Option.scala:145) [scala-library.jar:na] 
     at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$2.applyOrElse(PlayDefaultUpstreamHandler.scala:261) [play_2.10.jar:2.2.1] 
Caused by: javax.persistence.PersistenceException: org.hibernate.PersistentObjectException: detached entity passed to persist: models.MedicalIncident 
     at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1310) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1316) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.ejb.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:881) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at models.MedicalIncident.toDataBase(MedicalIncident.java:40) ~[na:na] 
     at controllers.MedicalIncidents.submit(MedicalIncidents.java:41) ~[na:na] 
Caused by: org.hibernate.PersistentObjectException: detached entity passed to persist: models.MedicalIncident 
     at org.hibernate.event.internal.DefaultPersistEventListener.onPersist(DefaultPersistEventListener.java:141) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.event.internal.DefaultPersistEventListener.onPersist(DefaultPersistEventListener.java:78) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.internal.SessionImpl.firePersist(SessionImpl.java:853) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.internal.SessionImpl.persist(SessionImpl.java:827) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.internal.SessionImpl.persist(SessionImpl.java:831) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.ejb.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:875) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
- 

-- (Running the application from SBT, auto-reloading is enabled) --- 

[info] play - Listening for HTTP on /0:0:0:0:0:0:0:0:8081 

(Server started, use Ctrl+D to stop and go back to the console...) 

[info] Compiling 1 Java source to /home/daniel/play-2.2.1/SupraCIRS/target/scala-2.10/classes... 

[info] Compiling 3 Scala sources and 1 Java source to /home/daniel/play-2.2.1/SupraCIRS/target/scala-2.10/classes... 
[info] play - datasource [jdbc:h2:mem:play] bound to JNDI as DefaultDS 
[info] play - database [default] connected at jdbc:h2:mem:play 
[error] application - 

! @6gh36abca - Internal server error, for (GET) [/] -> 

play.api.UnexpectedException: Unexpected exception[PersistenceException: [PersistenceUnit: defaultPersistenceUnit] Unable to build EntityManagerFactory] 
     at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:148) ~[play_2.10.jar:2.2.1] 
     at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:112) ~[play_2.10.jar:2.2.1] 
     at scala.Option.map(Option.scala:145) ~[scala-library.jar:na] 
     at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1.apply(ApplicationProvider.scala:112) ~[play_2.10.jar:2.2.1] 
     at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1.apply(ApplicationProvider.scala:110) ~[play_2.10.jar:2.2.1] 
     at scala.util.Success.flatMap(Try.scala:200) ~[scala-library.jar:na] 
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: defaultPersistenceUnit] Unable to build EntityManagerFactory 
     at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:924) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:899) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:59) ~[hibernate-entitymanager-4.2.6.Final.jar:4.2.6.Final] 
     at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63) ~[hibernate-jpa-2.0-api.jar:1.0.1.Final] 
     at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47) ~[hibernate-jpa-2.0-api.jar:1.0.1.Final] 
     at play.db.jpa.JPAPlugin.onStart(JPAPlugin.java:35) ~[play-java-jpa_2.10.jar:2.2.1] 
Caused by: org.hibernate.AnnotationException: No identifier specified for entity: models.MedicalIncident 
     at org.hibernate.cfg.InheritanceState.determineDefaultAccessType(InheritanceState.java:277) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.cfg.InheritanceState.getElementsToProcess(InheritanceState.java:224) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:665) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.cfg.Configuration$MetadataSourceQueue.processAnnotatedClassesQueue(Configuration.java:3533) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.cfg.Configuration$MetadataSourceQueue.processMetadata(Configuration.java:3487) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 
     at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1376) ~[hibernate-core-4.2.6.Final.jar:4.2.6.Final] 


    //end

這裏的類，在處理控制器表單提交

/** 
* Handle the form submission. 
*/ 
@Transactional 
public static Result submit() { 
    Form<MedicalIncident> filledForm = MedicalIncidentForm.bindFromRequest(); 

    if(filledForm.hasErrors()) { 
     return badRequest(form.render(filledForm)); 
    } else { 
     MedicalIncident created = filledForm.get(); 
     //return ok(confirmation.render("Twój incydent został zgłoszony poprawnie.")); 
     created.save(); 
     return ok(summary.render(created)); 
    } 
}

，這裏是我的模型類

package models; 

import java.util.*; 
import javax.persistence.*; 
import javax.persistence.Entity; 
import javax.validation.*; 
import play.data.validation.Constraints.*; 
import play.api.db.*; 
import play.db.jpa.*; 
import javax.persistence.EntityManager; 

@Entity 
public class MedicalIncident { 

    @Id 
    @GeneratedValue(strategy=GenerationType.AUTO) 
    public Long id; 

    @Required 
    public String month; 

    @Required 
    public String place; 

    @Required 
    public String unit; 

    @Required 
    public String incident_type; 

    @Required 
    public int age; 



    /** 
    * Insert this new incident submission. 
    */ 
    public void toDataBase() { 
     JPA.em().persist(this); 
    } 



}

普萊舍幫助我

來源

2013-12-11 masterdany88

我已經從模型中的MedicalIncident類中刪除了列表。 ANd錯誤不再顯示。現在，我在提交表格時出現此錯誤 [PersistenceException：org.hibernate.PersistentObjectException：傳遞給persist的分離實體：models.MedicalIncident] – masterdany88

從堆棧跟蹤我想你還沒有把一個@Id註解在MedicalIncident類的任何字段，但因爲你沒有發佈它，我不能確定。

Hibernate需要一個@Id字段來唯一標識一條記錄。

See hibernate docs。

來源

2013-12-11 11:46:21

我已經發布了整個類。我希望現在會更容易。我添加了@id註釋。但仍然相同 – masterdany88

它仍然是相同的堆棧跟蹤還是根本改變了？ –

已更改。我更新了所有代碼 – masterdany88

playframework org.hibernate.PersistentObjectException：傳遞給持久化的分離實體：模型

回答

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