獲取shell腳本中的行

我試圖獲取所有「RESP：0，成功;」輸入命令：RESP：0，成功; - 這裏是我的代碼，我會拿它嗎？獲取shell腳本中的行

**for i in {2..4} 
do 
    date 
    CMDCount="CMD"$i 
    eval CMD="$"$CMDCount 
    echo "server CMD "${CMD}""${CMDCount}""; 
    echo "" 
    (sleep 1;echo $login; 
    sleep 1;echo ${CMD}; 
    sleep 1;echo $logout;sleep 1)|telnet localhost 9685 
    sleep 1 

done**

輸出是這樣的：

server CMD xxxxxxxxxxxxxxxxxxxxxxxxxxxxCMD2 

Trying 127.0.0.1... 
Connected to localhost. 
Escape character is '^]'. 
CONNECTING TO xxx... 
PROCESS CPL CONNECTED... 
Enter command:RESP:0,sucess; 
Enter command: 
Enter command: 
Enter command:Connection closed by foreign host. 
Sat Aug 3 12:18:21 CST 2013 
server CMD xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxCMD3 

Trying 127.0.0.1... 
Connected to localhost. 
Escape character is '^]'. 
CONNECTING TO xxx... 
PROCESS CPL CONNECTED... 
Enter command:RESP:0,sucess; 
Enter command: 
Enter command: 
Enter command:Connection closed by foreign host. 
Sat Aug 3 12:18:26 CST 2013 
server CMD xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx;CMD4 

Trying 127.0.0.1... 
Connected to localhost. 
Escape character is '^]'. 
CONNECTING TO xxx... 
PROCESS CPL CONNECTED... 
Enter command:RESP:0,sucess; 
Enter command: 
Enter command: 
Enter command:Connection closed by foreign host.

來源

2013-08-03 hccccc

您可能會發現這些鏈接有用：

而且，爲了轉從整個字符串中取出響應部分，可以使用類似這樣的內容：

echo `expr "${CMD}" : '\.*?(RESP)(:)(\\d)\'`

來源

2013-08-03 12:43:36

獲取shell腳本中的行

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