JSON數據：從MySQL

<?php 
    require 'dbinfo.php'; 
    try { 
     $db = new PDO($dsn, $username, $password); 
     $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
     $sth = $db->query("SELECT * FROM user_tracks"); 
     $loc = $sth->fetchAll();  
     $locations = array_values($loc); 
     echo json_encode(array("user"=>($locations))); 
    } catch (Exception $e) { 
     echo $e->getMessage(); 
    } 
?>

獲取的代碼應該返回：JSON數據：從MySQL

{"user":[{"id":"1","Latitude":"12.9555033333","Longitude":"80.2461883333","Time":"06:32:57","Date":"2012-03-13","Speed":"0","Course":"183.92"},{...},{....}]}

當它返回：

{"user":[{"id":"1","0":"1","Latitude":"12.9555033333","1":"12.9555033333","Longitude":"80.2461883333","2":"80.2461883333","Time":"06:32:57","3":"06:32:57","Date":"2012-03-13","4":"2012-03-13","Speed":"0","5":"0","Course":"183.92","6":"183.92"},{...},{....}]}

我不確定發生了什麼......的問題在哪裏？

在此先感謝！

來源

2012-04-03 Karthick

fetchAll（）returns both（注意'fetch_style'參數註釋/註釋）字符串和數字鍵值來自查詢結果的默認數據。如果你只想要字符串版本，你必須做

$loc = $sth->fetchAll(PDO::FETCH_CLASS);

來源

2012-04-03 03:26:54

它的工作原理！它的另一種方式.. fetchAll（PDO :: FETCH_CLASS）;謝謝您的幫助！ – Karthick 2012-04-03 04:02:38

Woops，對。我的錯字。我會糾正答案。 – 2012-04-03 04:52:10

JSON數據：從MySQL

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