如何正確使用GSon和翻新

我想知道如何正確使用GSon和翻新？我從服務器接收到的JSON：如何正確使用GSon和翻新

{"tag":"getall","success":1,"error":0,"messages":[ 
{"message":"aaa","user_id":"111e9f66624637.88881557","time":"2014-10-17 21:27:29","usermail":"[email protected]"},{"message":"hdhxnd","user_id":"111e9f66624637.88881557","time":"2014-10-17 21:14:36","usermail":"[email protected]"},{"message":"zz","user_id":"111e9f66624637.88881557","time":"2014-10-17 21:11:15","usermail":"[email protected]"},{"message":"d","user_id":"111e9f66624637.88881557","time":"2014-10-17 18:16:35","usermail":"[email protected]"},{"message":"c","user_id":"111e9f66624637.88881557","time":"2014-10-17 18:15:16","usermail":"[email protected]"}]}

這是我的改裝方法：

public interface ConnectInterface { 
    @FormUrlEncoded 
    @POST("/") 
    void getUserMessages(@Field("tag") String first, @Field("device_id") String last, Callback<MyResponse> cb); 
}

MyResponse類：

public class MyResponse { 
    public List<Messages> messages; 
    public String success; 
    public String error; 
    public String tag; 

    public class Messages { 
     public String message; 
     public String user_id; 
     public String time; 
     public String usermail; 
    } 
}

和代碼的一部分，其使用它：

RestAdapter restAdapter = new RestAdapter.Builder() 
      .setEndpoint(URL) 
      .setErrorHandler(new MyErrorHandler()) 
      .build(); 

    ConnectInterface service = restAdapter.create(ConnectInterface.class); 
    Callback<MyResponse> stringCallback = new Callback<MyResponse>() { 
     @Override 
     public void success(MyResponse s, Response response) { 
      System.out.println(s.tag); 
      for(MyResponse.Messages messages: s.messages){ 
       System.out.println(messages.message); 
      } 
     } 

     @Override 
     public void failure(RetrofitError error) { 
      System.out.println(error.toString()); 
     } 
    }; 
    service.getUserMessages("getall", "4", stringCallback);

我是否以一種好的方式去做？什麼是

Gson gson = new GsonBuilder() 
setConverter(new GsonConverter(gson))

這些方法？

來源

2014-11-01 falsetto

你解決問題了嗎？ – pengwang 2014-12-01 08:21:42

使用gson.fromJson(String, Class)如下：

Gson gson = new Gson(); 
MyResponse myResponse = gson.fromJson(jsonString, MyResponse.class);

來源

2014-11-01 21:49:27

如何正確使用GSon和翻新

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