從OpenFire獲取所有用戶名和XMPP

Question

在我的應用程序中，我需要獲得所有的用戶名從OpenFire。

我用下面的代碼，但它不給零數據。

和我的事情是我的didReceiveIQ方法有問題，但使用第一次XMPP，所以不要得到實際問題。

我獲取數據的代碼是

- (void)getAllRegisteredUsers { 

NSError *error = [[NSError alloc] init]; 
NSXMLElement *query = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='http://jabber.org/protocol/disco#items' node='all users'/>" 
                 error:&error]; 
XMPPIQ *iq = [XMPPIQ iqWithType:@"get" 
          to:[XMPPJID jidWithString:[NSString stringWithFormat:@"Domain Name with jid"]] 
         elementID:[xmppStream generateUUID] child:query]; 
[xmppStream sendElement:iq]; 
} 

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq 
{ 
NSXMLElement *queryElement = [iq elementForName: @"query" xmlns: @"http://jabber.org/protocol/disco#items"]; 

NSLog(@"queryelement %@",queryElement); 

if (queryElement) { 

    NSLog(@"query in if"); 
    NSArray *itemElements = [queryElement elementsForName: @"item"]; 
    NSMutableArray *mArray = [[NSMutableArray alloc] init]; 
    for (int i=0; i<[itemElements count]; i++) { 

     NSString *jid=[[[itemElements objectAtIndex:i] attributeForName:@"jid"] stringValue]; 
     [mArray addObject:jid]; 

     NSLog(@"User in OpenFire = %@",jid); 

    } 

    NSLog(@"mArray = %@",mArray); 

} 

return NO; 
} 

任何形式的幫助表示讚賞....

Answer 1

通過這個代碼，你可以得到的名單列表（您來自openr fire server的朋友列表）。

NSXMLElement *query = [NSXMLElement elementWithName:@"query" xmlns:@"jabber:iq:roster"]; 

    NSXMLElement *iq = [NSXMLElement elementWithName:@"iq"]; 
    [iq addAttributeWithName:@"type" stringValue:@"get"]; 
    [iq addChild:query]; 
    [xmppStream sendElement:iq]; 

和響應將與您所期望的相同。

Answer 2

嘗試是這樣的：

[xmppRoster addDelegate:self delegateQueue:dispatch_get_main_queue() ] ; 
[xmppRoster fetchRoster ] ; 

你應該初始化的XMPPRoster前取名單：

xmppRosterStorage = [[XMPPRosterCoreDataStorage alloc] init]; 
// xmppRosterStorage = [[XMPPRosterCoreDataStorage alloc] initWithInMemoryStore]; 

xmppRoster = [[XMPPRoster alloc] initWithRosterStorage:xmppRosterStorage]; 

後你XMPPRoster對象發送fetchRoster，你可以從 XMPPRosterDelegate得到所有的用戶名的方法：

- (void)xmppRoster:(XMPPRoster *)sender didReceiveRosterItem:(NSXMLElement *)item 

希望這可以幫助：]

Answer 3

我有同樣的問題，我得到了queryElement爲零。我已經改變了響應代碼看到這樣的XML：

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq 
{ 
    NSXMLElement *queryElement = [iq elementForName:@"query" xmlns: @"jabber:iq:roster"]; 
    NSLog(@"IQ: %@",iq); 
    if (queryElement) { 

     NSArray *itemElements = [queryElement elementsForName: @"item"]; 
     NSMutableArray *mArray = [[NSMutableArray alloc] init]; 
     for (int i=0; i<[itemElements count]; i++) { 

      NSString *jid=[[[itemElements objectAtIndex:i] attributeForName:@"jid"] stringValue]; 
      NSLog(@"%@",jid); 
      [mArray addObject:jid]; 
     } 
    } 
    return NO; 
} 

Answer 4

我努力讓所有註冊用戶的Openfire到我的應用程序。我嘗試了所有上述方法，但沒有幫助我！ 嘗試了很多之後，我得到了所有的註冊用戶得到一個解決方案... 下面的代碼：

- (void)getAllRegisteredUsers { 

    NSError *error = [[NSError alloc] init]; 
    NSXMLElement *query = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='jabber:iq:roster'/>" error:&error]; 
    XMPPIQ *iq = [DDXMLElement elementWithName:@"iq"]; 
    [iq addAttributeWithName:@"type" stringValue:@"get"]; 
    [iq addAttributeWithName:@"none" stringValue:@"ANY_ID_NAME"]; 
    [iq addAttributeWithName:@"both" stringValue:@"ANY_ID_NAME"]; 
    [iq addChild:query]; 
    [xmppStream sendElement:iq]; 
} 

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq{ 

    NSXMLElement *queryElement = [iq elementForName: @"query" xmlns: @"jabber:iq:roster"]; 

    if (queryElement) { 
     NSArray *itemElements = [queryElement elementsForName: @"item"]; 
     NSMutableArray *mArray = [[NSMutableArray alloc] init]; 
     for (int i=0; i<[itemElements count]; i++) { 

      NSString *jid=[[[itemElements objectAtIndex:i] attributeForName:@"jid"] stringValue]; 
      [mArray addObject:jid]; 
     } 
     NSLog(@"%@",mArray); 
    } 
    return YES; 
} 

這爲我工作，希望它會爲別人工作，以及... :)