當我試圖重定向到其他網站,我收到此錯誤:笨重定向 - 您提交的URI已經不允許的字符
一個PHP錯誤遇到
嚴重性:警告
消息:parse_url(/%22 * * )[function.parse-URL]:無法解析URL
文件名:芯/ URI.php
行號:219
一個錯誤時遇到
您提交已禁用的字符的URI。
這是所有的代碼,我在URI.php
private function _detect_uri()
{
if (! isset($_SERVER['REQUEST_URI']) OR ! isset($_SERVER['SCRIPT_NAME']))
{
return '';
}
$uri = $_SERVER['REQUEST_URI'];
if (strpos($uri, $_SERVER['SCRIPT_NAME']) === 0)
{
$uri = substr($uri, strlen($_SERVER['SCRIPT_NAME']));
}
elseif (strpos($uri, dirname($_SERVER['SCRIPT_NAME'])) === 0)
{
$uri = substr($uri, strlen(dirname($_SERVER['SCRIPT_NAME'])));
}
// This section ensures that even on servers that require the URI to be in the query string (Nginx) a correct
// URI is found, and also fixes the QUERY_STRING server var and $_GET array.
if (strncmp($uri, '?/', 2) === 0)
{
$uri = substr($uri, 2);
}
$parts = preg_split('#\?#i', $uri, 2);
$uri = $parts[0];
if (isset($parts[1]))
{
$_SERVER['QUERY_STRING'] = $parts[1];
parse_str($_SERVER['QUERY_STRING'], $_GET);
}
else
{
$_SERVER['QUERY_STRING'] = '';
$_GET = array();
}
if ($uri == '/' || empty($uri))
{
return '/';
}
$uri = parse_url($uri, PHP_URL_PATH);
// Do some final cleaning of the URI and return it
return str_replace(array('//', '../'), '/', trim($uri, '/'));
}
正是它所說的 - 你是否試圖在CI源代碼中搜索該錯誤消息,並按照它的路徑來檢查這些字符的正則表達式?我敢打賭,改變這個正則表達式可以解決這個問題... –