有效和無效

你好，我有活動和非活動圖像代碼鏈接到數據庫表提交的狀態。有效和無效

現在，當我點擊激活或無效的記錄，所以它不工作。

下面是代碼：

的index.php

<!DOCTYPE html> 
<html> 
    <head> 
     <title></title> 
     <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> 
    </head> 
    <body> 
<?PHP 

$user_name = "root"; 
$password = ""; 
$database = "tariq"; 
$server = "localhost"; 

$db_handle = mysql_connect($server, $user_name, $password); 
$db_found = mysql_select_db($database, $db_handle); 

if ($db_found) { 

$SQL = "SELECT * FROM active"; 
$result = mysql_query($SQL); 

while ($db_field = mysql_fetch_assoc($result)) { 

if($db_field['status'] == 'Active') 
{ 
    echo "<a href='activate.php?status= Inactive' ><img src = 'inactive.jpg' /></a>"; 
} 
else 
{ 
     echo "<a href='activate.php?status= Active' ><img src = 'active.jpg' /></a>"; 
} 
} 

mysql_close($db_handle); 

} 
else { 

print "Database NOT Found "; 
mysql_close($db_handle); 

} 

?> 
    </body> 
</html>

活動.PHP

<?php 
$status = $_GET['status']; 
$con=mysqli_connect("localhost","root","","tariq"); 
if (mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
    } 
if($status == 'Active') 
{ 
    mysqli_query($con,"UPDATE `active` SET `status` = 'Inactive'"); 
} 
else 
{ 
    mysqli_query($con,"UPDATE `active` SET `status` = 'Active'"); 
} 
header('location:tariq.php'); 
mysqli_close($con); 
?>

來源

2014-02-23 user3295655

什麼「不工作？」 –

字段狀態未在數據庫中更新我已將查詢粘貼到phpmyadmin工作的界面中 – user3295655

當您點擊（active/inactive）鏈接並轉到'active.php'後重新加載'index.php'時發生了什麼？？它會改變狀態圖像嗎？ – SaidbakR

你有

<a href='activate.php?status= Inactive' > 
          ^.............here

在瀏覽器中的空間，當你點擊它會看起來的鏈接l IKE status=%20Inactive

和

<a href='activate.php?status= Active' > 
          ^.............here

刪除空間

<a href='activate.php?status=Inactive' > 
<a href='activate.php?status=Active' >

而且總是修剪（）的GET值

$status = trim($_GET['status']);

而且消毒GET值與mysqli_real_escape_string()

來源

2014-02-23 09:28:35

$ space =''; $ check = mysqli_real_escape_strin（$ con，$ space）; //不工作 – user3295655

對不起，我有一個錯字它的mysqli_real_escape_string（）http://in3.php.net/mysqli_real_escape_string –

仍然不能正常工作 – user3295655

檢查您的頁面名稱是否激活或激活？

來源

2016-12-10 04:43:39

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