使用Symfony和Doctrine擴展FilteringSelect/AutoComplete

Question

我有一個AutoComplete在下面的代碼中使用模型名稱。我很難將其擴展爲使自動填充包含品牌名稱。例如，如果有ST1和ST2型號的索尼品牌，我希望能夠鍵入索尼並獲得兩行 - 索尼ST1和索尼ST2，但是如果我鍵入ST1，我想要一個索尼排 - 索尼ST1。

控制器代碼

/** 
* @View() 
*/ 
public function getModelsAction(Request $request) 
{ 
    $this->denyAccessUnlessGranted('ROLE_ADMIN', null, 'Unable to access this page!'); 

    $modelName = str_replace('*', '%', $request->get('name')); 

    $em = $this->getDoctrine()->getManager(); 

    $queryBuilder = $em->createQueryBuilder() 
      ->select('m') 
      ->from('AppBundle:Model', 'm'); 

    $queryBuilder->where(
      $queryBuilder->expr()->like('m.name', '?1') 
    ); 
    $queryBuilder->setParameter(1, $modelName); 

    $query = $queryBuilder->getQuery(); 
    $modelCollection = $query->getResult(); 
    $data = []; 

    foreach($modelCollection as $m) 
    { 
     $item = [ 
      'id' => $m->getId(), 
      'name' => $m->getName(), 
     ]; 

     $data[] = $item; 
    } 
    return $data; 
} 

品牌和型號（註釋）

/** 
* @var ArrayCollection $brands 
* @ORM\ManyToMany(targetEntity="Model", cascade={"persist"}) 
* @ORM\JoinTable(name="brand_model", 
*  joinColumns={@ORM\JoinColumn(name="brand_id", referencedColumnName="id", onDelete="CASCADE")}, 
*  inverseJoinColumns={@ORM\JoinColumn(name="model_id", referencedColumnName="id", unique=true, nullable=false)} 
*  ) 
*/ 
protected $models = null; 

數據庫之間的連接

品牌

dev=# \d brand 
            Table "public.brand" 
    Column |    Type    |     Modifiers     
------------+--------------------------------+------------------------------------------- 
id   | integer      | not null 
name  | character varying(64)   | default NULL::character varying 
active  | boolean      | not null 
deleted_at | timestamp(0) without time zone | default NULL::timestamp without time zone 
comment | character varying(64)   | default NULL::character varying 
Indexes: 
    "brand_pkey" PRIMARY KEY, btree (id) 
Referenced by: 
    TABLE "manufacturer_brand" CONSTRAINT "fk_170c6d4844f5d008" FOREIGN KEY (brand_id) REFERENCES brand(id) 
    TABLE "brand_model" CONSTRAINT "fk_8c6cbbce44f5d008" FOREIGN KEY (brand_id) REFERENCES brand(id) ON DELETE CASCADE 

模式

dev=# \d model 
            Table "public.model" 
    Column |    Type    |     Modifiers     
------------+--------------------------------+------------------------------------------- 
id   | integer      | not null 
name  | character varying(64)   | default NULL::character varying 
comment | character varying(64)   | default NULL::character varying 
active  | boolean      | not null 
deleted_at | timestamp(0) without time zone | default NULL::timestamp without time zone 
Indexes: 
    "model_pkey" PRIMARY KEY, btree (id) 
Referenced by: 
    TABLE "brand_model" CONSTRAINT "fk_8c6cbbce7975b7e7" FOREIGN KEY (model_id) REFERENCES model(id) 

brand_model

dev=# \d brand_model 
    Table "public.brand_model" 
    Column | Type | Modifiers 
----------+---------+----------- 
brand_id | integer | not null 
model_id | integer | not null 
Indexes: 
    "brand_model_pkey" PRIMARY KEY, btree (brand_id, model_id) 
    "uniq_8c6cbbce7975b7e7" UNIQUE, btree (model_id) 
    "idx_8c6cbbce44f5d008" btree (brand_id) 
Foreign-key constraints: 
    "fk_8c6cbbce44f5d008" FOREIGN KEY (brand_id) REFERENCES brand(id) ON DELETE CASCADE 
    "fk_8c6cbbce7975b7e7" FOREIGN KEY (model_id) REFERENCES model(id) 

Answer 1

您可以更改查詢生成器：

$queryBuilder = $em->createQueryBuilder() 
    ->select('m.id, CONCAT(CONCAT(b.name, ' '), m.name)') 
    ->from('AppBundle:Model', 'm') 
    ->innerJoin('m.brands', 'b') 
    ->where("CONCAT(CONCAT(b.name, ' '), m.name)' LIKE :brand_model") 
    ->setParameter('brand_model', $brandModel) 
; 

確保您所定義的另一邊許多一對多的關係在你的Model實體：

class Model 
{ 
    // ... 
    /** 
    * @ManyToMany(targetEntity="Brand", mappedBy="models") 
    */ 
    private $brands; 
} 

現在你的控制器是小拜在->select(...)表達式定義的參數（無需使用foreach，學說會爲你做它）：

public function getModelsAction(Request $request) 
{ 
    // ... 
    // $queryBuilder = ... 

    $data = $queryBuilder->getQuery()->getResult(); 

    return $data; 
} 

注意，我改變的方式你的PHP編碼風格，以符合PSR編碼標準。