你將如何爲這個xml文件編寫一個可序列化的類？

我有這個XML文件，我想編寫一個可串行化的類用於XmlSerializer.Deserialize。你將如何爲這個xml文件編寫一個可序列化的類？

這裏的文件：

<?xml version="1.0" encoding="UTF-8"?> 
<dataroot 
    xmlns:od="urn:schemas-microsoft-com:officedata"  
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
    xsi:noNamespaceSchemaLocation="AFFEANALLECT.xsd" 
    generated="2011-02-02T13:27:46"> 
    <AFFEANALLECT> 
     <NUMEEMPL>4</NUMEEMPL> 
     <TYPETRAV>SOUD</TYPETRAV> 
     <CONTRAT>08245</CONTRAT> 
     <DATE>2008-03-27 14:09:59</DATE> 
     <STATION>02</STATION> 
     <HORAIRE>1</HORAIRE> 
     <ORIGINE>AFFE FIN</ORIGINE> 
    </AFFEANALLECT> 
    <AFFEANALLECT> 
     <NUMEEMPL>4</NUMEEMPL> 
     <TYPETRAV>SOUD</TYPETRAV> 
     <CONTRAT>08245</CONTRAT> 
     <DATE>2008-03-27 08:29:46</DATE> 
     <STATION>02</STATION> 
     <HORAIRE>1</HORAIRE> 
     <ORIGINE>AFFE DEBUT</ORIGINE> 
    </AFFEANALLECT> 
</dataroot>

我做了這樣的事情對於一個AFFEANALLECT：

[Serializable()] 
public class AFFEANALLECT 
{ 
    public string NUMEEMPL { get; set; } 
    public string TYPETRAV { get; set; } 
    public string CONTRAT { get; set; } 
    public string DATE  { get; set; } 
    public string STATION { get; set; } 
    public string HORAIRE { get; set; } 
    public string ORIGINE { get; set; } 
}

，它工作正常。現在唯一的辦法是將AFFEANALLECT放入一個名爲「dataroot」的哈希數組中。

請問您能指點我正確的方向嗎？

來源

2011-02-08 TomShreds

不要對XML序列化使用`[Serializable]`。它被忽略。 – 2011-02-08 13:49:13

感謝您的信息！ :) – TomShreds 2011-02-08 13:49:33

創建一類像AFFEANALLECTCOLLECTION：

[XmlRoot("dataroot)] 
public class AFFEANALLECTCOLLECTION 
{ 
    [XmlElement("AFFEANALLECT")] 
    public List<AFFEANALLECT> AFFEANALLECTS {get; set;} 

}

來源

2011-02-08 13:50:02 Aliostad

看一看屬性XMLSerializable及其選項，你可以得到的命名空間和XML文檔的屬性的精細控制。

來源

2011-02-08 13:50:43

如果我沒看錯的，如果你使用List<AFFEANALLECT>和連載這份名單中，你應該能夠讓你尋求

格式

來源

2011-02-08 13:51:03 RaM

Aliostad已經發布了具體情況下，一個完美的答案;但在一般情況下（具有一個xml fragement的）：

保存樣品某處爲
在VS命令提示，運行xsd foo.xml（這從XML生成一個xsd）
在VS命令在運行xsd foo.xsd /classes（這產生C＃從XSD）從foo.cs

拷貝在這種情況下（使用所有默認選項等）：

//------------------------------------------------------------------------------ 
// <auto-generated> 
//  This code was generated by a tool. 
//  Runtime Version:4.0.30319.1 
// 
//  Changes to this file may cause incorrect behavior and will be lost if 
//  the code is regenerated. 
// </auto-generated> 
//------------------------------------------------------------------------------ 

using System.Xml.Serialization; 

// 
// This source code was auto-generated by xsd, Version=4.0.30319.1. 
// 


/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] 
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] 
public partial class dataroot { 

    private datarootAFFEANALLECT[] aFFEANALLECTField; 

    private string generatedField; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("AFFEANALLECT", Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public datarootAFFEANALLECT[] AFFEANALLECT { 
     get { 
      return this.aFFEANALLECTField; 
     } 
     set { 
      this.aFFEANALLECTField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlAttributeAttribute()] 
    public string generated { 
     get { 
      return this.generatedField; 
     } 
     set { 
      this.generatedField = value; 
     } 
    } 
} 

/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] 
public partial class datarootAFFEANALLECT { 

    private string nUMEEMPLField; 

    private string tYPETRAVField; 

    private string cONTRATField; 

    private string dATEField; 

    private string sTATIONField; 

    private string hORAIREField; 

    private string oRIGINEField; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string NUMEEMPL { 
     get { 
      return this.nUMEEMPLField; 
     } 
     set { 
      this.nUMEEMPLField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string TYPETRAV { 
     get { 
      return this.tYPETRAVField; 
     } 
     set { 
      this.tYPETRAVField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string CONTRAT { 
     get { 
      return this.cONTRATField; 
     } 
     set { 
      this.cONTRATField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string DATE { 
     get { 
      return this.dATEField; 
     } 
     set { 
      this.dATEField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string STATION { 
     get { 
      return this.sTATIONField; 
     } 
     set { 
      this.sTATIONField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string HORAIRE { 
     get { 
      return this.hORAIREField; 
     } 
     set { 
      this.hORAIREField = value; 
     } 
    } 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] 
    public string ORIGINE { 
     get { 
      return this.oRIGINEField; 
     } 
     set { 
      this.oRIGINEField = value; 
     } 
    } 
} 

/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] 
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] 
public partial class NewDataSet { 

    private dataroot[] itemsField; 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("dataroot")] 
    public dataroot[] Items { 
     get { 
      return this.itemsField; 
     } 
     set { 
      this.itemsField = value; 
     } 
    } 
}

來源

2011-02-08 14:10:38

你將如何爲這個xml文件編寫一個可序列化的類？

回答

相關問題