在BindingSource中過濾DateTimePicker的日期值

Question

bsCheckVoucherGridView.Filter = 
    string.Format("[CHECK DATE] >= #{0:M/dd/yyyy}# ", 
    dateTimePicker_CheckVoucher_SearchCheckVoucherDate.Value);  
dateTimePicker_CheckVoucher_SearchCheckVoucherDate.Value = DateTime.Now.AddYears(-1); 
dateTimePicker_CheckVoucher_SearchCheckVoucherDate.Format = DateTimePickerFormat.Short; 
bsCheckVoucherGridView.DataSource = 
    db.GetDataTable("SELECT `CHECK_DATE` AS `CHECK DATE` FROM check_voucher"); 
bsCheckVoucherGridView.Filter = 
    string.Format("[CHECK DATE] >= {0:M/dd/yyyy} ", 
    dateTimePicker_CheckVoucher_SearchCheckVoucherDate.Value); 

上面的代碼在System.DateTime和System.Double上發生「Can not perform」> ='操作錯誤。

我要回答我的問題。

bsCheckVoucherGridView.Filter = 
    string.Format("[CHECK DATE] >= #{0}# ", 
    dateTimePicker_CheckVoucher_SearchCheckVoucherDate.Value.ToString("dd-MMM-yyyy")); 

這很好用！

Answer 1

，你可以做這樣的：

// Setup Filter and Sort Criteria 
    strExpr = "OrderDate >= '01.03.1998' AND OrderDate <= '31.03.1998'"; 
    // OR 
    // strExpr = "OrderDate >= #01.03.1998# AND OrderDate <= #31.03.1998#"; 
    strSort = "OrderDate DESC"; 

    // Use the Select method to find all rows matching the filter. 
    foundRows = myTable.Select(strExpr, strSort); 

全碼

private void BtnFilterAndSort_Click(object sender, System.EventArgs e) 
{ 
    string strText; 
    string strExpr; 
    string strSort; 
    DataRow[] foundRows; 
    DataTable myTable; 
    myTable = ds.Tables["Orders"]; 

    // Setup Filter and Sort Criteria 
    strExpr = "OrderDate >= '01.03.1998' AND OrderDate <= '31.03.1998'"; 
    strSort = "OrderDate DESC"; 

    // Use the Select method to find all rows matching the filter. 
    foundRows = myTable.Select(strExpr, strSort); 

    // Apply all Columns to the TextBox, this 
    // must be done Row-By-Row. 
    strText = null; 
    for (int i = 0 ; i <= foundRows.GetUpperBound(0); i++) 
    { 
    for (int j = 0; j <= foundRows[i].ItemArray.GetUpperBound(0); j++) 
    { 
     strText = strText + foundRows[i][j].ToString() + "\t"; 
    } 
    strText = strText + "\r\n"; 
    textBox.Text = strText; 
    } 
}