PowerShell：傳遞參數

Question

我在Jenkins的文件中運行腳本。命令：

psexec -i -s cmd.exe /c echo . | powershell.exe -file "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" 

如何傳遞「構建」變量的值？

請幫我 感謝

Answer 1

我的腳本出錯了。我忘了插入以下代碼：

Param(
    [int32]$build=0 
) 

As TheMadTechnician said，要運行腳本的命令是：

psexec -i -s cmd.exe /c echo . | powershell.exe -file "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" -build %BUILD_NUMBER% 

Answer 2

只需將遵循你的論點的路徑。如：

psexec -i -s cmd.exe /c echo . | powershell.exe -file "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" '-build 1.0' 

您可以看到PowerShell.exe的命令行語法here。它顯示：

PowerShell[.exe] 
     [-File <FilePath> [<Args>]] 

如果不爲你工作，你可以嘗試和點源在-command腳本塊的腳本，如：

psexec -i -s cmd.exe /c echo . | powershell.exe -command {. "c:\Program Files (x86)\Applications\Jenkins\jobs\Deploy\workspace\Deploy\script.ps1" -build 1}